The rate at which an object move is it's

Which items in this picture provide insulation?

Verdich [7]

Answer:wdym insulation if u mean like covering than the ppls heads

Explanation:

5 0

4 years ago

A 50 kg boy is at the edge of a circular platform of radius 4.0 m which is rotating freely

Flauer [41]

Answer:

0.62 rad/s

Explanation:

Angular momentum is conserved.

I₁ ω₁ = I₂ ω₂

where I is moment of inertia and ω is angular velocity.

The total moment of inertia is the sum of the platform's inertia and the boy's.

(I + m r₁²) ω₁ = (I + m r₂²) ω₂

Given I = 1000 kg m², m = 50 kg, r₁ = 4.0 m, r₂ = 3.0 m, and ω₁ = 0.5 rad/s:

(1000 + 50 (4.0)²) (0.5) = (1000 + 50 (3.0)²) ω₂

900 = 1450 ω₂

ω₂ = 0.62 rad/s

8 0

3 years ago

The Earth can be approximated as a sphere of uniform density, rotating on its axis once a day. The mass of the Earth is 5.97×10^

ser-zykov [4K]

I had the same quiz… it’s a

8 0

3 years ago

Consider a air-filled parallel-plate capacitor with plates of length 8 cm, width 5.52 cm, spaced a distance 1.99 cm apart. Now i

prohojiy [21]

Answer:

The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

Explanation:

Given that,

Length of plates = 8 cm

Width = 5.52 cm

Distance = 1.99 cm

Dielectric constant = 2.6

Length = 4.4 cm

Potential = 0.8 V

We need to calculate the initial capacitance

Using formula of capacitance

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times8\times5.52\times10^{-4}}{1.99\times10^{-2}}$

$C=1.96\times10^{-12}$

We need to calculate the final capacitance

Using formula of capacitance

$C'=\dfrac{\epsilon_{0}A_{1}}{d}+\dfrac{k\epsilon_{0}A_{2}}{d}$

Put the value into the formula

$C'=(\dfrac{8.85\times10^{-12}}{1.99\times10^{-2}})((4.4\times5.52)+(3.6\times5.52)2.6)\times10^{-4}$

$C'=3.37\times10^{-12}$

We need to calculate the ratio of the new potential energy to the potential energy before the insertion of the dielectric

Using formula of energy

$\dfrac{E}{E'}=\dfrac{\dfrac{1}{2}CV^2}{\dfrac{1}{2}C'V^2}$

Put the value into the formula

$\dfrac{E}{E'}=\dfrac{1.96\times10^{-12}}{3.37\times10^{-12}}$

$\dfrac{E}{E'}=0.58$

Hence, The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

4 0

3 years ago

Tell me the other form of vf=vi+at

drek231 [11]

FIRST EQUATION OF MOTION
Vf = Vi + at Consider a body initial moving with velocity "Vi". After a certain interval of time "t", its velocity becomes "Vf". NowChange in velocity = Vf - Vi 
OR
DV =Vf – ViDue to change in velocity, an acceleration "A" is produced in the body. Acceleration is given bya = DV/t Putting the value of "DV"a = (Vf – Vi)/t
at = Vf – Vi
at + Vi =Vf
OR
Vf = Vi + at


--------------------hope it helped you-------------------
****************plz mark the brainliest*************

4 0

4 years ago