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SIZIF [17.4K]
3 years ago
9

The picture on the left represents the reactants in the equation and the picture on the right represents the products. Does this

reaction follow the law of conservation of matter?
• No,there are different kinds of atoms are present in the products as in the reactants.

•No, because there are new products than the reactants.

•No, because there are not the same number of molecules in the product side as in the reactant side.

•yes, the same number and kind of atoms are present in the products as in the reactants.

Physics
1 answer:
V125BC [204]3 years ago
7 0
The answer is , n<span>o, because there are not the same number of molecules in the product side as in the reactant side. 

The law of conservation of matter says that the system remains the same throughout. The number of atoms, mass and energy must stay constant. If you look at your figure there are more white atoms on the left side than the right, this means that there was a loss and this should not be the case. 
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Katyanochek1 [597]
I think it would be the one talking about if there’s water there would still be energy because water is used as a source of energy because there’s so much of it and it can be used again and again
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14. Saeed is pulling a 6 kg heavy rock with an upward force of 40 N but does not succeed to lift it up. What is the magnitude of
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Answer:

58.8 N

Explanation:

The normal force is calculated as equal to the perpendicular component of the gravitational force.

Thus; N = mg

We are given m = 6 kg

Thus;

N = 6 × 9.8

N = 58.8 N

Thus, magnitude of normal force on the rock = 58.8 N

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2 years ago
The diagram below shows the heating of an unknown substance (it is not water). Its melting point is? The diagram below shows the
Anettt [7]

Answer:

the answer is B

Melting point, temperature at which the solid and liquid forms of a pure substance can exist in equilibrium. As heat is applied to a solid, its temperature will increase until the melting point is reached. More heat then will convert the solid into a liquid with no temperature change.

4 0
2 years ago
A rocket has landed on planet x, which has half the radius of earth. An astronaut onboard the rocket weighs twice as much on pla
Nastasia [14]

Answer:

Option (c) u0

Explanation:

The escape velocity has a formula as:

V = √(2gR)

Where V is the escape velocity,

g is the acceleration due to gravity

R is the radius of the earth.

Now, from the question, we were told that the escape velocity for the rocket taking off from earth is u0 i.e

V(earth) = u0

V(earth) = √(2gR)

u0 = √(2gR) => For the earth

Now, let us calculate the escape velocity for the rocket taking off from planet x. This is illustrated below below:

g(planet x) = 2g (earth) => since the weight of the astronaut is twice as much on planet x as on earth

R(planet x) = 1/2 R(earth) => planet x has half the radius of earth

V(planet x) =?

Applying the formula V = √(2gR), the escape velocity on planet x is obtained as follow:

V(planet x) = √(2g(x) x R(x))

V(planet x) = √(2 x 2g x 1/2R)

V(planet x) = √(2 x g x R)

V(planet x) = √(2gR)

The expression obtained for the escape velocity on planet x i.e V(planet x) = √(2gR), is exactly the same as that obtained for the earth i.e V(earth) = √(2gR)

Therefore,

V(planet x) = V(earth) = √(2gR)

But from the question, V(earth) is u0

Therefore,

V(planet x) = V(earth) = √(2gR) = u0

So, the escape velocity on planet x is u0

4 0
3 years ago
When you throw a ball up in the air, it travels up and then stops instantaneously before falling back down. At the point where i
Gnoma [55]

Answer:

The ball stops instantaneously at the topmost point of the motion.

Explanation:

Assume we have thrown a ball up in the air. For that we have given a force on the ball and it acquires an initial velocity in the upward direction.

The forces that resist the motion of the ball in the upward direction are the force of gravity and air resistance. The ball will instantaneously come to rest when the velocity of the ball reduces to zero.

The two forces acting in the downward direction reduces its speed continuously and it becomes zero at the topmost point.

4 0
3 years ago
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