The picture on the left represents the reactants in the equation and the picture on the right represents the products. Does this
reaction follow the law of conservation of matter?
• No,there are different kinds of atoms are present in the products as in the reactants.
•No, because there are new products than the reactants.
•No, because there are not the same number of molecules in the product side as in the reactant side.
•yes, the same number and kind of atoms are present in the products as in the reactants.
• No,there are different kinds of atoms are present in the products as in the reactants.
•No, because there are new products than the reactants.
•No, because there are not the same number of molecules in the product side as in the reactant side.
•yes, the same number and kind of atoms are present in the products as in the reactants.
1 answer:
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Data:
KE (Kinetic Energy) = ? (Joule)
m (mass) = 1500 Kg
v (speed) = 42 Km/h
converting to m/s (42 / 3.6), we have: v (speed) = 11.6 m/s
Formula:
Solving:
KE (Kinetic Energy) = ? (Joule)
m (mass) = 1500 Kg
v (speed) = 42 Km/h
converting to m/s (42 / 3.6), we have: v (speed) = 11.6 m/s
Formula:
Solving:
Answer:
141.78 ft
Explanation:
When speed, u = 44mi/h, minimum stopping distance, s = 44 ft = 0.00833 mi.
Calculating the acceleration using one of Newton's equations of motion:
Note: The negative sign denotes deceleration.
When speed, v = 79mi/h, the acceleration is equal to when it is 44mi/h i.e. -116206.48 mi/h^2
Hence, we can find the minimum stopping distance using:
The minimum stopping distance is 141.78 ft.