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SIZIF [17.4K]
3 years ago
9

The picture on the left represents the reactants in the equation and the picture on the right represents the products. Does this

reaction follow the law of conservation of matter?
• No,there are different kinds of atoms are present in the products as in the reactants.

•No, because there are new products than the reactants.

•No, because there are not the same number of molecules in the product side as in the reactant side.

•yes, the same number and kind of atoms are present in the products as in the reactants.

Physics
1 answer:
V125BC [204]3 years ago
7 0
The answer is , n<span>o, because there are not the same number of molecules in the product side as in the reactant side. 

The law of conservation of matter says that the system remains the same throughout. The number of atoms, mass and energy must stay constant. If you look at your figure there are more white atoms on the left side than the right, this means that there was a loss and this should not be the case. 
</span>
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An electron in a TV picture tube is accelerated through a potential difference of 10 kV before it hits the screen. What is the k
laiz [17]

Answer:

10,000 eV

Explanation:

According to the law of conservation of energy, the kinetic energy gained by the electron is equal to its change in electric potential energy:

K=\Delta U=q \Delta V

where:

K is the kinetic energy of the electron

q=1 e is the magnitude of the charge of the electron

\Delta V is the potential difference through which the electron has been accelerated

For this electron in the TV, we have

\Delta V=10 kV=10000 V

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4 years ago
A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A cons
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Complete Question

A ball having mass 2 kg is connected by a string of length 2 m to a pivot point and held in place in a vertical position. A constant wind force of magnitude 13.2 N blows from left to right. Pivot Pivot F F (a) (b) H m m L L If the mass is released from the vertical position, what maximum height above its initial position will it attain? Assume that the string does not break in the process. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m.What will be the equilibrium height of the mass?

Answer:

H_m=1.65m

H_E=1.16307m

Explanation:

From the question we are told that

Mass of ball M=2kg

Length of string L= 2m

Wind force F=13.2N

Generally the equation for \angle \theta is mathematically given as

tan\theta=\frac{F}{mg}

\theta=tan^-^1\frac{F}{mg}

\theta=tan^-^1\frac{13.2}{2*2}

\theta=73.14\textdegree

Max angle =2*\theta= 2*73.14=>146.28\textdegree

Generally the equation for max Height H_m is mathematically given as

H_m=L(1-cos146.28)

H_m=0.9(1+0.8318)

H_m=1.65m

Generally the equation for Equilibrium Height H_E is mathematically given as

H_E=L(1-cos73.14)

H_E=0.9(1+0.2923)

H_E=1.16307m

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3 years ago
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5) [Honors]A seagull, ascending straight upward at 5.2 m/s, drops a shell when it is 12.5m above the ground. (A)
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Answer:

(B) 13.9 m

(C) 1.06 s

Explanation:

Given:

v₀ = 5.2 m/s

y₀ = 12.5 m

(A) The acceleration in free fall is -9.8 m/s².

(B) At maximum height, v = 0 m/s.

v² = v₀² + 2aΔy

(0 m/s)² = (5.2 m/s)² + 2 (-9.8 m/s²) (y − 12.5 m)

y = 13.9 m

(C) When the shell returns to a height of 12.5 m, the final velocity v is -5.2 m/s.

v = at + v₀

-5.2 m/s = (-9.8 m/s²) t + 5.2 m/s

t = 1.06 s

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