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hram777 [196]
3 years ago
11

A rocket starting from its launch pad is subjected to a uniform acceleration of 100 meters/second2. Determine the time needed to

reach the final velocity of 1,000 meters/second.
Physics
1 answer:
balandron [24]3 years ago
5 0
The velocity is the integral of acceleration.  If acceleration is 100 m/s^2 then velocity is:

v= \int\limits^{}_{}100 \, dt=100t

So to know the velocity at any time, t, we just put t in seconds into this equation.  To know at what time we get to a certain velocity, we set this equation equal to that velocity and solve for t:

100t = 1000 \\  \\  t= \frac{1000}{100} =10s

 
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A 240 cm length of string has a mass of 2.5 g. It is stretched with a tension of 8.0 N between fixed supports. (a) What is the w
kotykmax [81]

Answer:

a.87.6 m/s

b.18.25 Hz

Explanation:

the equation for the wave speed is expressed as

v=\sqrt{\frac{Tl}{m}}\\

where v is the speed,

           T is the tension in Newton

           l is the length

and      m is the mass

Now since

T=8.0N\\m=2.5g=0.0025kg\\l= 240cm=2.40cm\\

by substituting values into the equation, we have

v=\sqrt{\frac{8*2.40}{0.0025} } \\v=87.6m/s\\

b. the expression for the frequency is giving as

Frequency,f=\frac{v}{2l} \\f=\frac{87.6}{2*2.40} \\f=18.25Hz\\.

Note we 2L as the wavelength because we solving for the fundamental frequency as stated in the question.

3 0
3 years ago
Which vector is the sum of the vectors shown below?
Vinil7 [7]
The answer is going to be C
5 0
3 years ago
The average standard rectangular building brick has a mass of 3.10 kg and dimensions of 225 m x 112 m x 75 m. The gravitational
zzz [600]

Answer:

P=3.61\times 10^{-3}\ Pa

Explanation:

Given that,

Mass of a brick, m = 3.1 kg

The dimensions of the brick 225 m x 112 m x 75 m

We need to find the maximum pressure created by the brick. We know that, the force acting per unit area is called pressure exerted. It is given by the formula as follows :

P=\dfrac{F}{A}

F = mg

A = area with minimum dimensions i.e. 112 m x 75 m

Pressure is maximum when the area is least.

So,

P=\dfrac{mg}{A}\\\\P=\dfrac{3.1\times 9.8}{112\times 75}\\\\P=3.61\times 10^{-3}\ Pa

So, the maximum pressure created by brick is 3.61\times 10^{-3}\ Pa.

5 0
3 years ago
Mrs. Lynn's art class is making pencil holders out of soup cans. Each student is first covering a can with felt. What will the c
DochEvi [55]

Answer:

25.13 cm

Explanation:

Mrs. Lynn's art class is making pencil holders out of soup cans

These soup cans are definitely in cylindrical forms.

Each student is first covering a can with felt.

A felt is a type of material that is used for covering other objects. Here a felt is used to cover soup cans.

So if the diameter of the bottom of the can is 8 cm (i.e d = 8cm)

What will the circumference of the piece of felt need to be in order to cover the bottom of the can?

The felt will also take the circumference of a cylinder; and which is given by the expression

C = 2 πr

since diameter (d) = 8 cm

radius (r) = \frac{d}{2}

r = \frac{8}{2}

r = 4 cm

C = 2 × π × 4 cm

C = 2 × 3.142 × 4 cm

C = 25.13 cm

∴ the circumference of the piece of felt need to be 25.13 cm in order to cover the bottom of the can.

6 0
3 years ago
If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the
PolarNik [594]

Answer:

a. v₁ = 16.2 m/s

b. μ = 0.251

Explanation:

Given:

θ = 15 ° , r = 100 m , v₂ = 15.0 km / h

a.

To determine v₁ to take a 100 m radius curve banked at 15 °

tan θ  = v₁² / r * g

v₁ = √ r * g * tan θ

v₁ = √ 100 m * 9.8 m/s² * tan 15° = 16.2 m/s

b.

To determine μ friction needed for a frightened

v₂ = 15.0 km / h * 1000 m / 1 km * 1h / 60 minute * 1 minute / 60 seg

v₂ = 4.2 m/s

fk = μ * m * g

a₁ = v₁² / r = 16.2 ² / 100 m = 2.63 m/s²

a₂ = v₂² / r = 4.2 ² / 100 m = 0.18 m/s²

F₁ = m * a₁  ,  F₂ = m * a₂

fk = F₁ - F₂   ⇒  μ * m * g = m * ( a₁ - a₂)

μ * g = a₁ - a₂   ⇒  μ = a₁ - a₂ / g

μ = [ 2.63 m/s² - 0.18 m/s² ] / (9.8 m/s²)

μ = 0.251

3 0
3 years ago
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