Answer:
a.87.6 m/s
b.18.25 Hz
Explanation:
the equation for the wave speed is expressed as

where v is the speed,
T is the tension in Newton
l is the length
and m is the mass
Now since

by substituting values into the equation, we have

b. the expression for the frequency is giving as
.
Note we 2L as the wavelength because we solving for the fundamental frequency as stated in the question.
The answer is going to be C
Answer:

Explanation:
Given that,
Mass of a brick, m = 3.1 kg
The dimensions of the brick 225 m x 112 m x 75 m
We need to find the maximum pressure created by the brick. We know that, the force acting per unit area is called pressure exerted. It is given by the formula as follows :

F = mg
A = area with minimum dimensions i.e. 112 m x 75 m
Pressure is maximum when the area is least.
So,

So, the maximum pressure created by brick is
.
Answer:
25.13 cm
Explanation:
Mrs. Lynn's art class is making pencil holders out of soup cans
These soup cans are definitely in cylindrical forms.
Each student is first covering a can with felt.
A felt is a type of material that is used for covering other objects. Here a felt is used to cover soup cans.
So if the diameter of the bottom of the can is 8 cm (i.e d = 8cm)
What will the circumference of the piece of felt need to be in order to cover the bottom of the can?
The felt will also take the circumference of a cylinder; and which is given by the expression
C = 2 πr
since diameter (d) = 8 cm
radius (r) = 
r = 
r = 4 cm
C = 2 × π × 4 cm
C = 2 × 3.142 × 4 cm
C = 25.13 cm
∴ the circumference of the piece of felt need to be 25.13 cm in order to cover the bottom of the can.
Answer:
a. v₁ = 16.2 m/s
b. μ = 0.251
Explanation:
Given:
θ = 15 ° , r = 100 m , v₂ = 15.0 km / h
a.
To determine v₁ to take a 100 m radius curve banked at 15 °
tan θ = v₁² / r * g
v₁ = √ r * g * tan θ
v₁ = √ 100 m * 9.8 m/s² * tan 15° = 16.2 m/s
b.
To determine μ friction needed for a frightened
v₂ = 15.0 km / h * 1000 m / 1 km * 1h / 60 minute * 1 minute / 60 seg
v₂ = 4.2 m/s
fk = μ * m * g
a₁ = v₁² / r = 16.2 ² / 100 m = 2.63 m/s²
a₂ = v₂² / r = 4.2 ² / 100 m = 0.18 m/s²
F₁ = m * a₁ , F₂ = m * a₂
fk = F₁ - F₂ ⇒ μ * m * g = m * ( a₁ - a₂)
μ * g = a₁ - a₂ ⇒ μ = a₁ - a₂ / g
μ = [ 2.63 m/s² - 0.18 m/s² ] / (9.8 m/s²)
μ = 0.251