Answer:
180 meters
Explanation:
Josh walks 6 meters to the right and the 6 meters back. This means that in one time, Josh walks a total distance of 6+6 = 12 meters
Now, we are given that Josh walks this same distance 15 times.
Therefore, we will multiply this distance by 15 to get the total distance that he walks as follows:
Total distance = 12*15 = 180 meters
Based on the above calculations, Josh walks 180 meters over the course of the class
Hope this helps :)
Answer: Graph C is the correct option
Explanation:
The question is incomplete, please remember to submit the whole question :)
However, the rest of the question with its corresponding figures is below:
Assume that positive momentum is to the right, which of the following best represents the momentum of the cart of mass m as a function of time before and after the collision?
The initial momentum
of the cart with mass
(before the collision) is:
(1) Note the negative sign indicates the direction of cart's velocity (to the left, as seen in the first image attached)
On the other hand, the final momentum
of both carts (after the inelastic collision) is:
(2)
So, according to this, the correct graph tha best represents the situation is C. Since before the collision the momentum is negative, then both carts slow down after the collision (
), and taking into account the linear momentum is directly proportional to the velocity
(although is in the positive direction) is less than
.
What's 950 x 10 bro?
<span>
9500 kg m/s</span>
Answer:
This is as a result that about the central axis a collapsed hollow cone is equivalent to a uniform disc
Explanation:
The integration of the differential mass of the hollow right circular cone yields

and for a uniform disc
I = 1/2πρtr⁴ = 1/2Mr².
Answer:
work output is always less than work input - the ratio is less than 1.
Explanation:
This principle comes from the fact that a machine or system cannot produce more work than is supplied to it, because this would violate the energy conservation law (work is a type of mechanical energy).
In theoretical machines called "ideal machines" the input work is the same as the output work, but these machines are only theoretical because in real applications there is always some type of energy loss, either in heat produced by a machine or processes for its operation, for this reason the output work is always less than the input work.
Regarding the ratio work output to work input:

because work input WI is always greater than work output WO.