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Kitty [74]
3 years ago
10

Two tuning forks produce sounds of wavelengths 3.4 meters and 3.3 meters. Given that the speed of sound is 340 m/s, approximatel

y what beat frequency is produced when both tuning forks are struck simultaneously?
A) 0.1 hertz
B) 1.0 hertz
C) 2.0 hertz
D) 3.0 hertz
E) 4.0 hertz
Physics
1 answer:
Zinaida [17]3 years ago
7 0

Answer:3.0hertz

Explanation:

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You observe two cars traveling in the same direction on a long, straight section of Highway 5. The red car is moving at a consta
Romashka-Z-Leto [24]

Answer:

a) 3.66 s

b) 124.4 m

c) 3.12s

Explanation:

Given that

Speed of the Red Car, v₁ = 34 m/s

Speed of the Blue Car, v₂ = 28 m/s

Distance between the two cars, d = 22 m

The difference between the speed of the cars is: 34 - 28 = 6 m/s

From this, we can deduce that the red car will be catching up to the blue car at a speed of 6 m/s.

1)

If we divide the distance by the difference in speed. This becomes

d/v = 22/6 = 3.66 s. Which means, It takes 3.66 seconds for the red car to meet up with the blue car.

2

From the previous part, we were able to confirm that it took 3.66 seconds for the red car to meet up the blue car. Also, the speed with which it were traveling was travelling at, was constant, so we only need to multiply it by the time from (1) to get the distance.

v = d * t = 34 * 3.66 = 124.4

Therefore the red car travels at 124.4 m before catching up to the blue car.

3

If the red car starts to accelerate the moment we see it, the time it will take, to get to the blue car will be less than what we had gotten. We can find this using one of the equations of motion.

S = ut + ½gt², where

S = 22

u = 6

t = ?

g = 2/3

22 = 6t + 1/3t²

By using the quadratic formula, we find out the two answers listed below

t1 = 3.12 s

t2 = - 21.12 s

We all know that negative time is not possible, so the answer is t1. At 3.12 seconds

8 0
3 years ago
A harmonic force of maximum value 25 N and frequency of 180 cycles>min acts on a machine of 25 kg mass. Design a support syst
kramer

Answer:

registrar y de h2rhrjlekeek tert2h2jwkwlwlwlwlwlwñlwk

3 0
3 years ago
A solid sphere rolls without slipping down an incline, starting from rest. At the same time, a box starts from rest at the same
NISA [10]

Answer:

The box arrives first.

Explanation:

Hope this helps!! :))

Learn more at :

brainly.com/question/20164917

4 0
2 years ago
A sinusoidal, transverse wave that propagates in the positive x-direction can be described with the wave function y of xt is equ
myrzilka [38]

Answer:

\omega =\frac{2 \pi }{T} rad/s

Explanation:

The wave function is:

y(xt) = Acos(kx- \omega t)

where :

k = wave number

x = position of a point on the wave

\omega = angular frequency

t = time

What is another way to express the angular frequency (omega)

Angular frequency (omega) can be express as :

\omega =\frac{2 \pi }{T} rad/s ( i.e one repetition that it takes to repeats itself)

4 0
3 years ago
A potential difference of 1.20 V will be applied to a 33.0 m length of 18-gauge copper wire (diameter = 0.0400 in.). Calculate (
Nostrana [21]

Answer:A) Current = 1.739A, B)current density, J = 2.147x10^6 A/m2

magnitude of electric field , E =  0.036 N/C

)rate of thermal energy, P  =2.086W

Explanation:

Resistance  = R =   ρL/A

But the cross-section area of the wire. is given as

Diameter / 2 = 0.04/2 =0.02in to m = 0.02 / 39.37= 0.000508

A = πr^2 = π x  0.000508^2 = 8.10 x 10^-7

since resistivity of copper,ρ= 17x10-9 ohm.m

so resistance is   R =   ρL/A

17x10-9  x 33 / 8.1x10-7

= 0.69 ohm.

A) Current =    I = Voltage /Resistance =1.20/0.69 =1.739A

B)current density, J = Current /Area

= 1.739/8.1x10-7

= 2.147x10^6 A/m2

c)magnitude of electric field , E =  Current density x resistivity =J ρ

E = 2.147 x 10^6  x 17  x 10^-9

E = 0.036 N/C

D)rate of thermal energy, P  = I² R =1.739² X 0.69

=2.086W

6 0
3 years ago
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