Answer:
Change in internal energy (ΔU) = -9 KJ
Explanation:
Given:
q = –8 kJ [Heat removed]
w = –1 kJ [Work done]
Find:
Change in internal energy (ΔU)
Computation:
Change in internal energy (ΔU) = q + w
Change in internal energy (ΔU) = -8 KJ + (-1 KJ)
Change in internal energy (ΔU) = -8 KJ - 1 KJ
Change in internal energy (ΔU) = -9 KJ
I’m pretty positive the answer is True
Answer:
It is referred to as the van't Hoff factor.
Explanation:
The van't Hoff factor is named after the Dutch chemist Jacobus Henricus van 't Hoff. It can also be defined as the ratio of the actual quantity of particles to the quantity of particles for no ionization.The fundamental assumption of the van't Hoff factor is that the substance is a nonelectrolyte.
Answer:
123 g/mol
Explanation:
Let's consider the neutralization reaction.
H₂Z(aq) + 2 NaOH(aq) → Na₂Z(aq) + 2 H₂O(ℓ)
The moles of NaOH that reacted are:
The molar ratio of H₂Z to NaOH is 1:2. The moles of H₂Z that reacted are:
The molar mass of H₂Z is:
