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s344n2d4d5 [400]
3 years ago
10

What is the difference between cellular respiration and photosynthesis

Chemistry
1 answer:
guapka [62]3 years ago
3 0
Cellular respiration<span> is a set of metabolic reactions and processes that take place in the cells of organisms to convert biochemical energy from nutrients into adenosine triphosphate (ATP), and then release waste products
</span>
<span>Photosynthesis</span>- the process by which green plants and some other organisms use sunlight to synthesize foods from carbon dioxide and water. Photosynthesis in plants generally involves the green pigment chlorophyll and generates oxygen as a byproduct.

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GIVE THE DEFINITION OF EACH WORD.
KATRIN_1 [288]

1. a group of resources treated as a single entity that accepts a combination of materials and instructions to add value through a series of operations; may be either automated or manual.

2. a group of cells that have similar structure and that function together as a unit. A nonliving material, called the intercellular matrix, fills the spaces between the cells.

3. a differentiated structure (such as a heart, kidney, leaf, or stem) consisting of cells and tissues and performing some specific function in an organism.

4. a group of organs that work together to perform a certain function in an organism's body.

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7 0
2 years ago
What is volume if the diameter of a sphere is 14cm<br>​
lisov135 [29]
Volume = (4/3) × π × r^3
R = 1/2 D
R = 7

V = 4/3 x π x 7^3

Exact Form:
1372 π/ 3

Decimal Form:
1436.75504024

6 0
3 years ago
Chemistry help! Thanks to anyone who helps!
zmey [24]
A: 2-methyl-2-propanom
5 0
2 years ago
Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction:
Leni [432]

Answer:

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8 0
2 years ago
What is the pH of 0.10 M NaF(aq). The Ka of HF is 6.8 x 10-4
dsp73

<u>Given information:</u>

Concentration of NaF = 0.10 M

Ka of HF = 6.8*10⁻⁴

<u>To determine:</u>

pH of 0.1 M NaF

<u>Explanation:</u>

NaF (aq) ↔ Na+ (aq) + F-(aq)

[Na+] = [F-] = 0.10 M

F- will then react with water in the solution as follows:

F- + H2O ↔ HF + OH-

Kb = [OH-][HF]/[F-]

Kw/Ka = [OH-][HF]/[F-]

At equilibrium: [OH-]=[HF] = x and [F-] = 0.1 - x

10⁻¹⁴/6.8*10⁻⁴ = x²/0.1-x

x = [OH-] = 1.21*10⁻⁶ M

pOH = -log[OH-] = -log[1.21*10⁻⁶] = 5.92

pH = 14 - pOH = 14-5.92 = 8.08

Ans: (b)

pH of 0.10 M NaF is 8.08

6 0
2 years ago
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