Question

At what pressure would 11.1 moles of a gas occupy 44.8 L at 300 K?

Answer 1

Answer:

$P=6.10atm$

Explanation:

Hello,

In this case, we can study the ideal gas equation that relates temperature, volume, pressure and moles as shown below:

$PV=nRT$

Thus, since we are asked to compute the pressure y simply solve for it as follows:

$P=\frac{nRT}{V}=\frac{11.1mol*0.082\frac{atm*L}{mol*K}*300K}{44.8L}\\ \\P=6.10atm$

Best regards.