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PtichkaEL [24]
3 years ago
10

Sophie and Simon are peeling a pile of potatoes for lunch in the cafeteria. Sophie can peel all the potatoes by herself in 45 mi

nutes, while it would take Simon 30 minutes to do the job working alone. If Sophie and Simon work together to peel the potatoes, how long will it take them? 15 minutes 18 minutes 38 minutes 75 minutes
Mathematics
2 answers:
tensa zangetsu [6.8K]3 years ago
6 0
Short Answer: 18 minutes
Remark

The answer to this problem is less than the smallest time of the two people working together. that fact lets out C and D (38 minutes and 75 minutes). Now you have to choose 15 minutes and 18 minutes. There's a method. No guessing needed.

Givens
Let the time for Sophie = S
Let the time for Simon = M
Let the job to completion = 1 
S = 45 minutes
M = 30 minutes

Step One
Convert minutes to hours.
45 minutes = 45 / 60 = 3/4 hour = 0.75 hour
30 minutes = 30 / 60 = 1/2 hour = 0.50 hour

Step Two
Set up the Equation
The formula is a form of job / hour.
Let the time = t that they both have to work

job = 1 in these problems.
1/S + 1/M = 1/t
1/0.75 + 1/0.5 = 1/t

Solve
1 ÷ 0.75 = 1.33333
1 ÷ 0.5 = 2

1.3333 + 2 = 3.33333 
3.3333 = 1 / t                    Multlply both sides by t
3.3333*t = 1
t = 1 / 3.333333333
t = 0.3 of an hour


1 hour = 60 minutes
0.3 hours = x              Cross Multiply
x = 60 * 0.3
x = 18 minutes

Answer working together it took them 18 minutes  <<<<< 
qwelly [4]3 years ago
3 0

Answer:

b

Step-by-step explanation:

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A quiz has five true or false questions. How many possible ways could the five questions be answered?
dybincka [34]

Answer:

The total number of ways to answer = 32

Step-by-step explanation:

A quiz has five questions that can be answered as true or false.

Each question can be answered in two ways.

Lets take each question one by one.

The first question can be answered as true or false that is two ways.

Similarly each question answered in 2 ways.

To get the total number of ways, we have to multiply the number of ways for each question.

Hence the total number of questions = 2\times 2\times 2\times 2\times 2

                                     = 32

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2 years ago
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Ray Of Light [21]

Answer:

it means it is less than one

6 0
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Julie and her family go to the movies. They buy 2 adult tickets and 3 child tickets. An adult ticket costs $3.50 more than a chi
EastWind [94]

Answer:

$9.25

Step-by-step explanation:

let x = the cost of a child ticket

3(x)+2(x+3.50)=35.75

3x+2x+7=35.75

5x=28.75

x=5.75 cost of child ticket

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7 0
3 years ago
Read 2 more answers
A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len
Gnom [1K]

Answer:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

df=n-1=93-1=92  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

\bar X=5.97 represent the sample mean for the length

s=0.4 represent the sample standard deviation

n=93 sample size  

\mu_o =6 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:  

Null hypothesis:\mu = 6  

Alternative hypothesis:\mu \neq 6  

since we don't know the population deviation the statistic is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing in formula (1) we got:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

P value

The degrees of freedom are given by:

df=n-1=93-1=92  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0
3 years ago
????????????????????
Ilia_Sergeevich [38]

Answer:

your answer would be D....

3 0
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