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3 years ago

How many moles of H2O will be formed from the reaction of 80 g of

Chemistry

1 answer:

Roman55 [17]3 years ago

4 0

Answer: 2 moles of $H_2O$ will be formed.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} NaOH=\frac{80g}{40g/mol}=2moles$

The balanced chemical equation is:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

According to stoichiometry :

2 moles of $NaOH$ give = 2 moles of $H_2O$

Thus 2 moles of $NaOH$ give = $\frac{2}{2}\times 2=2moles$ of $H_2O$

Thus 2 moles of $H_2O$ will be formed.

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3 years ago

A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out 192.mg of oxalic acid H2

kap26 [50]

Answer:

The molarity of the NaOH solution is 0.076 M

Explanation:

Step 1: Data given

Mass of oxalic acid = 192 mg = 0.192 grams

volume = 250 mL = 0.250 L

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Step 2: The balanced equation

H2C2O4 + 2NaOH → Na2C2O4 + H2O

Step 3: Calculate moles of oxalic acid

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Step 4: Calculate molarity of oxalic acid

Molarity = Moles / volume

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Molarity = 0.00852 M

Step 5: Calculate Molarity of NaOH

2 Ca*Va = Cb*Vb

with Ca = Molarity of oxalic acid = 0.00852 M

with Va = volume of oxalic acid = 0.250 L

with Cb = Molarity of NaOH = TO BE DETERMINED

with Vb = volume of 0.0558 L

Cb = (2*0.00852 * 0.25) / 0.0558

Cb = 0.076 M

The molarity of the NaOH solution is 0.076 M

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3 years ago

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3 years ago

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