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GrogVix [38]
3 years ago
13

How many moles of H2O will be formed from the reaction of 80 g of

Chemistry
1 answer:
Roman55 [17]3 years ago
4 0

Answer: 2 moles of H_2O will be formed.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} NaOH=\frac{80g}{40g/mol}=2moles

The balanced chemical equation is:

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

According to stoichiometry :

2 moles of NaOH give = 2 moles of H_2O

Thus 2 moles of NaOH give =\frac{2}{2}\times 2=2moles of H_2O

Thus 2 moles of H_2O will be formed.

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tino4ka555 [31]

Answer:

WHAT??

Explanation:

3 0
3 years ago
Read 2 more answers
Which of the following acids is in household vinegar? A nitric acid hydrochloric acid C fluoric acid D acetic acid
Free_Kalibri [48]

Answer: Out of the given options acetic acid is in household vinegar.

Explanation:

Household vinegar is the one that is commonly used in our home while cooking a number of dishes.

The common name of vinegar is acetic acid and its chemical formula is CH_{3}COOH.

For example, vinegar (acetic acid) is used while making noodles.

Thus, we can conclude that out of the given options acetic acid is in household vinegar.

7 0
3 years ago
An enzyme can catalyze a reaction with either of two substrates, S1 or S2. The Km for S1 was found to be 2.0 mM, and the Km, for
Lera25 [3.4K]

Answer:

100.5 ≈ 101

Explanation:

Km for S1 = 2.0 mM

Km for S2 = 20 mM

Given that : S1 = S2 =  hence Vmax for either S1 or S2 can represent

The Vmax can be calculated using the data Given and equation below

Vo = Vmax [s] / ( Km + [s] )  ------ (1)

Vo = 0.5

[s] = 0.1 mM

km = 20 mM

making Vmax subject of  equation 1

Vmax = 0.5 ( 20.1 mM) / (0.1 mM )

         = 100.5 ≈ 101

3 0
3 years ago
How much of each gas is there in 100cm3 air?
Akimi4 [234]
Each 100 cm3 of air, constitutes 78cm3 nitrogen, 21cm3 oxygen and 1cm3 constitutes of other gases like Argon, ozone, carbon dioxide and water vapour in small amounts.
8 0
4 years ago
Read 2 more answers
The density of water is 1.00 g/ml at 4°c. how many water molecules are present in 2.56 ml of water at this temperature?
o-na [289]

Answer:

             8.55 × 10²² Molecules

Solution:

Step 1: Calculate the Mass of Water as;

                       Density  =  Mass ÷ Volume

Solving for Mass,

                       Mass  =  Density × Volume

Putting values,

                       Mass  =  1 g.mL⁻¹ × 2.56 mL

                       Mass  =  2.56 g

Step 2: Calculate Moles of Water as,

                       Moles  =  Mass ÷ M.Mass

Putting values,

                       Moles  =  2.56 g ÷ 18 g.mol⁻¹

                       Moles  =  0.142 mol

Step 3: Calculate Number of Molecules of Water as,

                       # of Molecules  =  Moles × 6.022 × 10²³

Putting value of mole,

                       # of Molecules  =  0.142 × 6.022 × 10²³

                       # of Molecules  =  8.55 × 10²² Molecules

5 0
4 years ago
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