Question

How many moles of H2O will be formed from the reaction of 80 g of

Answer 1

Answer: 2 moles of $H_2O$ will be formed.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$    

$\text{Moles of} NaOH=\frac{80g}{40g/mol}=2moles$

The balanced chemical equation is:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

According to stoichiometry :

2 moles of $NaOH$ give = 2 moles of $H_2O$

Thus 2 moles of $NaOH$ give =$\frac{2}{2}\times 2=2moles$ of $H_2O$

Thus 2 moles of $H_2O$ will be formed.