How to memorize the periodic table

1 answer:

5 0

Well I remember when i learned about that there was a goofy little rap on YouTube and just listen to it like 10 times and boom you know where gold is on the periodic chart. Sorry if this doesn't help but good luck !! Lol

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What is the empirical formula for a compound that is 29.44\% calcium, 23.55% sulfur, and 47.01% oxygen? This compound is a commo

PSYCHO15rus [73]

Answer:

Empirical formula is CaSO₄.

Explanation:

Given data:

Percentage of calcium =29.44%

Percentage of sulfur = 23.55%

Percentage of oxygen = 47.01%

Empirical formula = ?

Solution:

Number of gram atoms of Ca = 29.44 / 40 = 0.74

Number of gram atoms of S = 23.55 / 32 = 0.74

Number of gram atoms of O = 47.01 / 16 = 3

Atomic ratio:

Ca : S : O

0.74/0.74 : 0.74/0.74 : 3/0.74

1 : 1 : 4

Ca : S : O = 1 : 1 : 4

Empirical formula is CaSO₄.

3 0

3 years ago

How many grams of oxygen gas will be produced when 2.50 moles of potassium chlorate is decomposed?

yawa3891 [41]

Answer:

$m_{O_2}=120gO_2$

Explanation:

Hello!

In this case, since the decomposition of potassium chlorate is:

$2KClO_3\rightarrow 2KCl+3O_2$

We can see a 2:3 mole ratio between potassium chlorate and oxygen (molar mass 32.0 g/mol), thus, via stoichiometry, we compute the mass of oxygen that are produced by the decomposition of 2.50 moles of this reactant:

$m_{O_2}=2.50molKClO_3*\frac{3molO_2}{2molKClO_3} *\frac{32.0gO_2}{1molO_2}\\\\m_{O_2}=120gO_2$