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iren [92.7K]
4 years ago
14

Stone is on ground at rest ,what are forces acting on it

Physics
1 answer:
zhenek [66]4 years ago
3 0

gravity is acting on the rock with the ground :)

the force is a gravitational pull

hope this helps!

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A car with mass 1500 kg moves with constant velocity of 36 m/s. The driver sees a group of cows in front and he immediately step
Crazy boy [7]
From laws of motion:

S = ( \frac{v + u}{2} ) \times t
Where S is the distance/displacement (as you would call it) which is unknown
v = final velocity which is 0m/s (this is because the car stops)
u = initial velocity which is 36m/s (from the data given)
t = time taken for the distance to be covered and it is 6s


Substitute the values, hence:
S = ( \frac{0 + 36}{2} ) \times 6
S = (18) \times 6 \\  \\ S = 108m

But this is merely the distance he travelled in the 6 seconds he was trying to stop the car.

Therefore, the distance between the car and the cows = 160-108
Distance = 52m
6 0
4 years ago
During an early phase of the planet's existence, earth's atmosphere was similar in composition to the atmospheres of mars and ve
KengaRu [80]

The answer is carbon dioxide. This primordial earths’ atmosphere was composed by gasses from degassing of the earth's interior after its formation. It is after the beginning of life that oxygen levels began to rise and levels of carbon dioxide began to reduce in the atmosphere (as a result of photosynthesis).

8 0
4 years ago
A car is going 25 mph along a flat road. This is an example of what kind of energy?
monitta
This is most likely an example of kinetic energy.
3 0
3 years ago
Read 2 more answers
When you turn on a battery-powered flashlight, you transform
tia_tia [17]
The answer should be B) Chemical energy into electrical energy and light since the flashlight is being turned into light in order to see.
6 0
4 years ago
A box at rest has the shape of a cube 3.5 m on a side. This box is loaded onto the flat floor of a spaceship and the spaceship t
guapka [62]

Answer:

V_o=25.725\ m^3

Explanation:

Given:

sides of the cube, a=3.5\ m

speed of the cube with respect to the observer, v=0.8c

Since the relative velocity of the object is relativistic, so there will be a length contraction according to the observer:

a_o=a\div\frac{1}{\sqrt{1-\frac{v^2}{c^2} } }

where:

a_o= observed length of the side along the direction of velocity

a_o=3.5\div\frac{1}{\sqrt{1-\frac{(0.8c)^2}{c^2} } }

a_o=2.1\ m is the observed length of the cube edge only in the direction of the velocity due to relativistic effect of length contraction.

So the observed volume will be:

V_o=a\times a\times a_o

V_o=3.5\times 3.5\times 2.1

V_o=25.725\ m^3

5 0
3 years ago
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