In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. This law means that energy can neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another.
It mainly depends on the season of the year
Heavy-duty cords will have a marking on the insulation such as letters which indicates its properties.
<h3>What are Heavy duty cords?</h3>
Heavy duty cords comprises of insulators which helps prevent cases of electric shock. There are usually letters written on them which indicates the nature of insulation and other properties.
For example, the "S" in "SO" stands for "Extra Hard Service and the "O" stands for oil resistant.
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a measurable variable and a subjective opinion.
Explanation:
Testable hypothesis that leads to experiments usually describes a relationship between a measurable variable and a subjective opinion.
In testing a hypotheses through experiments, we often design our work to suit the use of two variables which are the measurable variable and the subjective opinion.
- This often takes the shape of dependent and independent variables in an experiment.
- Measurable variables can either be dependent, independent or controlled variables.
- The subjective opinion is the scientific logic that governs hows two or more variables are related.
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Answer:
a) F₁₂₀ = 1.34 pa A , b) F₂₀ = 0.746 pa A
Explanation:
Part. A
. The definition of pressure is
P = F / A
As the air can approach an ideal gas we can use the ideal gas equation
P V = n R T
Let's write this equation for two temperatures
P₁ V = n R T₁
P₂2 V = n R T₂
P₁ / P₂ = T₁ / T₂
point 1 has a pressure of P₁ = pa and a temperature of (20 + 273) K, point 2 is at (120 + 273) K, we calculate the pressure P₂
P₂ = P₁ T₂ / T₁
P₂ = pa 393/293
P₂ = 1.34 pa
We calculate the strength
P₂ = F₁₂₀ / A
F₁₂₀ = 1.34 pa A
Part B
In this case the data is
Point 1 has a temperature of 393K and an atmospheric pressure (P₁ = pa), point 2 has a temperature of 293K, let's calculate its pressure
P₁ / P₂ = T₁ / T₂
P₂ = P₁ T₂ / T₁
P₂ = pa 293/393
P₂ = 0.746 pa
Let's calculate the force (F20), from this point
F₂₀ / A = 0.746 pa
F₂₀ = 0.746 pa A
