What is the formula for speed or velocity?

Why should galaxy collisions have been more common in the past than they are today?

Roman55 [17]

Answer:

I think d is the answer haha

7 0

4 years ago

A spaceship accelerates uniformly for 1220km how much time is needed for the spaceship to increase its speed from 11.1km/s to 11

snow_lady [41]

The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s is 107 s

<h3>Data obtained from the question</h3>

The following data were obtained from the question given above:

Initial velocity (u) = 11.1 Km/s
Final velocity (v) = 11.7 Km/s
Distance (s) = 1220 Km
Time (t) =?

<h3>How to determine the time</h3>

The time taken for the spaceship to increase its speed from 11.1 km/s to 11.7 km/s can be obtained as illustrated below:

s = (u + v)t / 2

Cross multiply

(u + v)t = 2s

Divide both sides by (u + v)

t = 2s / (u + v)t

t = (2 × 1220) / (11.1 + 11.7)

t = 2440 / 22.8

t = 107 s

Thus, the time taken for the spaceship to change its speed is 107 s

Learn more about speed:

brainly.com/question/680492

Learn more about velocity:

brainly.com/question/3411682

#SPJ1

6 0

2 years ago

N in-ground swimming pool has the dimensions shown in the drawing. It is filled with water to a uniform depth of 3.00 m. The den

Doss [256]

Answer:

The pressure is $P = 1.31*10^{5} \ Pa$

Explanation:

From the question we are told that

The depth of the swimming pool is $d = 3.00 \ m$

The density of water is $\rho = 1.00*10^{3} \ kg /m^3$

Generally the total pressure exerted on the bottom of the swimming pool is mathematically represented as

$P = P_o + \rho * g * h$

Here $P_o$ is the atmospheric pressure with value

$P_o = 101325 \ Pa$

So

$P = 101325 + [1000 * 9.8 * 3]$

=> $P = 130725 \ Pa$

=> $P = 1.31*10^{5} \ Pa$

7 0

3 years ago

If a flea can jump straight up to a height of 0.410 m , what is its initial speed as it leaves the ground?

aivan3 [116]

Initial velocity = $v_0$

acceleration in the downward direction = -9.8 $\frac {m}{s^2}$

Final velocity at the highest point = 0

Maximum height reached = 0.410 m

Now, Using third equation of motion:

$\(v^2 = {v_0}^{2} + 2aH$

$\(0^2 = {v_0}^{2} - 2 \times 9.8 \times 0.410$

${v_0}^{2} = 2 \times 9.8 \times 0.410$

$v_0 = 2.834 \frac {m}{s}$

Speed with which the flea jumps = $2.834 \frac {m}{s}$

4 0

4 years ago

Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial spe

Novosadov [1.4K]

Consider horizontal component: Using the formula:v2=u2+2a<span>s</span>
<span>0=(16sin<span>470</span><span>)2</span>+2(−9.81)s</span><span>s=6.98m</span><span>=7.0m(2s.f.)</span>The maximu height from the ground is 8.5m

4 0

3 years ago