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andreev551 [17]
3 years ago
15

Jenna used 256 cups of blueberries to make pancakes. kenneth used 112 times the amount of blueberries as jenna used. to find the

number of cups of blueberries kenneth used, you can solve 112⋅256. write the answer as a mixed number in simplest form.
Mathematics
1 answer:
topjm [15]3 years ago
3 0
256 x
112
=28,672
This is a whole number, so I wonder if you might have missed something in the question?
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A gondola (cable car) at a ski area holds 50 people. Its maximum safe load is 10000 pounds. A population of skiers has a distrib
fenix001 [56]

Answer:   0.03855

Step-by-step explanation:

Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.

Its maximum safe load is 10000 pounds.

Let X denotes the weight of 50 people.

As per given ,

Population mean weight of 50 people = \mu=50\times190=9500\text{ pounds}

Standard deviation of 50 people =\sigma=40\sqrt{50}=40(7.07106781187)=282.84

Then , the probability its maximum safe load will be exceeded =

P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855

Thus , the probability its maximum safe load will be exceeded = 0.03855

3 0
4 years ago
Can someone show me the steps to solving this <br> (Rationalizing Denominator)
Crazy boy [7]

Answer:

\huge  \purple {\frac{2 \sqrt[3]{6} +  \sqrt[3]{18} }{  6}  }

Step-by-step Explanation:

\huge \frac{2 +  \sqrt[3]{3} }{ \sqrt[3]{6} }  \\  \\  =  \huge \frac{(2 +  \sqrt[3]{3} )}{ \sqrt[3]{6} }  \times  \frac{ \sqrt[3]{6}  \times  \sqrt[3]{6} }{\sqrt[3]{6}  \times  \sqrt[3]{6}}  \\  \\ =  \huge \frac{(2 +  \sqrt[3]{3} )}{ \sqrt[3]{6} }  \times  \frac{ \sqrt[3]{6 ^{2} }  }{\sqrt[3]{6^{2}}  } \\  \\ =  \huge \frac{(2 +  \sqrt[3]{3} )\sqrt[3]{6} }{ \sqrt[3]{6} \times \sqrt[3]{6 ^{2} }}  \\  \\ =  \huge \frac{(2 \sqrt[3]{6} +  \sqrt[3]{3} \sqrt[3]{6} )}{  \sqrt[3]{6 ^{3} }}  \\  \\ =  \huge  \orange{\frac{2 \sqrt[3]{6} +  \sqrt[3]{18} }{  6}  }

6 0
3 years ago
Solve a triangle with a = 25, b = 30, and C= 160°.
larisa86 [58]

Answer:

a

Step-by-step explanation:

8 0
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19) A submarine dives to a depth of 657 feet below sea
Misha Larkins [42]

Answer:

To bring the submarine back to the sea level, it have to move 578 feet upwards

Step-by-step explanation:

Given:

Initially the depth the submarine dives  =  657 feet below sea

The height the submarine moves up =  79 feet

To Find :

Change in its depth required to bring the submarine back to the sea level  = ?

Solution :

In initially the Submarine will be at the depth of  657 feet below sea

when it goes up, the the depth reduces

657 - 79  = 578 feet

Now the submarine will be the depth of  578 feet

Now the submarine have to move  578 feet upwards to reach the sea level

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3 years ago
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