It will be 25.7435 i hope that the right answer
Answer: 0.03855
Step-by-step explanation:
Given :A population of skiers has a distribution of weights with mean 190 pounds and standard deviation 40 pounds.
Its maximum safe load is 10000 pounds.
Let X denotes the weight of 50 people.
As per given ,
Population mean weight of 50 people =
Standard deviation of 50 people 
Then , the probability its maximum safe load will be exceeded =
![P(X>10000)=P(\dfrac{X-\mu}{\sigma}>\dfrac{10000-9500}{282.84})\\\\=P(z>1.7671-8)\\\\=1-P(z\leq1.7678)\ \ \ \ [\because\ P(Z>z)=P(Z\leq z)]\\\\=1-0.96145\ \ \ [\text{ By p-value of table}]\\\\=0.03855](https://tex.z-dn.net/?f=P%28X%3E10000%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B10000-9500%7D%7B282.84%7D%29%5C%5C%5C%5C%3DP%28z%3E1.7671-8%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1.7678%29%5C%20%5C%20%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3Ez%29%3DP%28Z%5Cleq%20z%29%5D%5C%5C%5C%5C%3D1-0.96145%5C%20%5C%20%5C%20%5B%5Ctext%7B%20By%20p-value%20of%20table%7D%5D%5C%5C%5C%5C%3D0.03855)
Thus , the probability its maximum safe load will be exceeded = 0.03855
Answer:
Step-by-step Explanation:
![\huge \frac{2 + \sqrt[3]{3} }{ \sqrt[3]{6} } \\ \\ = \huge \frac{(2 + \sqrt[3]{3} )}{ \sqrt[3]{6} } \times \frac{ \sqrt[3]{6} \times \sqrt[3]{6} }{\sqrt[3]{6} \times \sqrt[3]{6}} \\ \\ = \huge \frac{(2 + \sqrt[3]{3} )}{ \sqrt[3]{6} } \times \frac{ \sqrt[3]{6 ^{2} } }{\sqrt[3]{6^{2}} } \\ \\ = \huge \frac{(2 + \sqrt[3]{3} )\sqrt[3]{6} }{ \sqrt[3]{6} \times \sqrt[3]{6 ^{2} }} \\ \\ = \huge \frac{(2 \sqrt[3]{6} + \sqrt[3]{3} \sqrt[3]{6} )}{ \sqrt[3]{6 ^{3} }} \\ \\ = \huge \orange{\frac{2 \sqrt[3]{6} + \sqrt[3]{18} }{ 6} }](https://tex.z-dn.net/?f=%20%5Chuge%20%5Cfrac%7B2%20%2B%20%20%5Csqrt%5B3%5D%7B3%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B6%7D%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Chuge%20%5Cfrac%7B%282%20%2B%20%20%5Csqrt%5B3%5D%7B3%7D%20%29%7D%7B%20%5Csqrt%5B3%5D%7B6%7D%20%7D%20%20%5Ctimes%20%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B6%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B6%7D%20%7D%7B%5Csqrt%5B3%5D%7B6%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B6%7D%7D%20%20%5C%5C%20%20%5C%5C%20%3D%20%20%5Chuge%20%5Cfrac%7B%282%20%2B%20%20%5Csqrt%5B3%5D%7B3%7D%20%29%7D%7B%20%5Csqrt%5B3%5D%7B6%7D%20%7D%20%20%5Ctimes%20%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7B6%20%5E%7B2%7D%20%7D%20%20%7D%7B%5Csqrt%5B3%5D%7B6%5E%7B2%7D%7D%20%20%7D%20%5C%5C%20%20%5C%5C%20%3D%20%20%5Chuge%20%5Cfrac%7B%282%20%2B%20%20%5Csqrt%5B3%5D%7B3%7D%20%29%5Csqrt%5B3%5D%7B6%7D%20%7D%7B%20%5Csqrt%5B3%5D%7B6%7D%20%5Ctimes%20%5Csqrt%5B3%5D%7B6%20%5E%7B2%7D%20%7D%7D%20%20%5C%5C%20%20%5C%5C%20%3D%20%20%5Chuge%20%5Cfrac%7B%282%20%5Csqrt%5B3%5D%7B6%7D%20%2B%20%20%5Csqrt%5B3%5D%7B3%7D%20%5Csqrt%5B3%5D%7B6%7D%20%29%7D%7B%20%20%5Csqrt%5B3%5D%7B6%20%5E%7B3%7D%20%7D%7D%20%20%5C%5C%20%20%5C%5C%20%3D%20%20%5Chuge%20%20%5Corange%7B%5Cfrac%7B2%20%5Csqrt%5B3%5D%7B6%7D%20%2B%20%20%5Csqrt%5B3%5D%7B18%7D%20%7D%7B%20%206%7D%20%20%7D)
Answer:
a
Step-by-step explanation:
Answer:
To bring the submarine back to the sea level, it have to move 578 feet upwards
Step-by-step explanation:
Given:
Initially the depth the submarine dives = 657 feet below sea
The height the submarine moves up = 79 feet
To Find :
Change in its depth required to bring the submarine back to the sea level = ?
Solution :
In initially the Submarine will be at the depth of 657 feet below sea
when it goes up, the the depth reduces
657 - 79 = 578 feet
Now the submarine will be the depth of 578 feet
Now the submarine have to move 578 feet upwards to reach the sea level