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Troyanec [42]
3 years ago
10

A 25-mL solution of H2SO4 is completely neutralized by 18 mL of 1.0M NaOH. What is the concentration of the H2SO4?

Chemistry
2 answers:
photoshop1234 [79]3 years ago
6 0

Answer : The correct option is, (D) 0.36 M

Explanation :

Using neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity of an acid = 2

n_2 = acidity of a base = 1

M_1 = concentration of H_2SO_4 = ?

M_2 = concentration of NaOH = 1.0 M

V_1 = volume of H_2SO_4 = 25 ml

V_2 = volume of NaOH = 18 ml

Now put all the given values in the above law, we get the concentration of the H_2SO_4.

2\times M_1\times 25ml=1\times 1.0M\times 18ml

M_1=0.36M

Therefore, the concentration of the H_2SO_4 is, 0.36 M

Charra [1.4K]3 years ago
5 0
There are several information's already given in the question. Based on the information's provided, the answer can be easily deduced.
V1 = 25 ml
     = 25/1000 liter
     = 0.025 liter
V2 = 18 ml
      = 18/1000 liter
      = 0.018 liter
M2 = 1.0 M
M1 = ?
Then
M1V1 = M2V2
M1 = M2V2/V1
      = (1 * 0.018)/0.025
      = 0.72 M
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your help.
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b) Mass of MnO₂ = 5.981 g

    Mass of H₂O = 1.2384 g

c) Total Mass of Reactant consumed = 11.708 g

b) Given Reaction

            Zn(s) + MnO₂(s) + H₂O(l) → ZnO(s) + Mn(OH)₂(s)

  Mass of Zn = 4.50 g

  Moles of Zn = 0.0688 moles

   Now,

    Moles of Zn = moles of MnO₂ = moles of H₂O = moles of ZnO = moles of                   Mn(OH)₂

Hence ,

Moles of MnO₂ = 0.0688 moles

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                        = 5.981 g

Similarly,

    Moles of H₂O = 0.0688 moles

     Mass of H₂O = 0.0688 × 18 g

                           = 1.2384 g

c) now ,

    Moles of  ZnO = 0.0688 moles

     Mass of  ZnO  = 0.06880× 81.3794 g

                              = 5.598 g

 Moles of  Mn(OH)₂ = 0.0688 moles

  Mass of  Mn(OH)₂ =0.0688 × 88.952 g

                                  = 6.11 g

Total mass of Product = 11.708 g

Total Mass of Reactant = 11.715 g

Hence,

    Total mass of reactant consumed = 11.708 g

c)  As total mass of reactant is more than that of mass of reactant consumed , Hence G is more than that of mass of reactant consumed .

G = - nFEcell

 

and no. of moles of reactant  is greater than that of number of moles of reactant consumed .

       Hence voltaic cell of given Capacity are heavier than that of mass of reactant consumed .

 Thus from above conclusion we can say that , Mass of the reactant consumed is 11.708 g.

Learn more about Galvanic Cell here : brainly.com/question/19340007

#SPJ4

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