You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:
<em>a(t)</em> = 40 ft/s²
<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>
<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>
<em />
<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>
<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>
<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²
<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²
I believe that the answer is C.
Its C! Lets say x=30
|30-323|=50
This could technically be true because it would show if the temp is within range
The answer will be 388.6 because you will use the formula V=pi.r^2.h.
pi we know is 3.14 we also know that radius is half the diameter so half of 5 is 2.5 and the height is 9 so here is what we have so far. V=3.14x2.5^2x9.
2.5x2.5=13.75 13.75x3.14=43.175 43.175x9=388.575 and if we round that it will be 388.6 so your answer is 388.6
Answer:
24.96%
Step-by-step explanation:
HOPE I WAS FAST ENOUGH
