89.1% Au
The molar mass of Au2O3 is 2(196.97) + 3(16.00) = 441.94 g/mol
The mass percent of Au is therefore 2(196.97) / 441.94, which is 393.94/441.94 = 0.891 —> 89.1%
<span>amount of heat and energy(energy of fusion)</span>
Answer:
The number of atoms in 1 mole silver is also 6.022 *10^23 atoms.
Option C is correct.
Explanation:
Step 1: Data given
Mass of 1 mole silver = 107.9 grams
Step 2: Calculate the number of atoms in 1 mole of silver
To calculate the number of atoms in 1 mole, we multiply the number of Avogadro by the number of moles
Number of atoms = 1 mol * 6.022 *10^23 atoms/ mol
Number of atoms = 6.022 * 10^23 atoms
Since the number of Avogadro says there are 6.022 * 10^23 atoms per 1 mole. The number of atoms in 1 mole silver is also 6.022 *10^23 atoms.
Option C is correct.
I think it would be better control of fusion reactions.
