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Drupady [299]
3 years ago
5

Which are the possible reactants of these products?

Chemistry
2 answers:
algol133 years ago
8 0
I think its d 2h20 + o2
zhenek [66]3 years ago
3 0

Answer: Option (C) is the correct answer.

Explanation:

When we write a chemical reaction equation then reactants are written on left hand side whereas products are written on right hand side.

And a chemical reaction in which a compound dissociates to given two products is known as a decomposition or dissociation reaction.

For example, 2H_{2}O_{2} \rightarrow 2H_{2}O + O_{2}

Therefore, 2H_{2}O_{2} is the reactant and both 2H_{2}O and O_{2} are the products.

Thus, we can conclude that out of the given options 2H_{2}O_{2} are the possible reactants of these products.

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The table shows four solutions that were prepared by
Yuliya22 [10]

Answer:

a

Explanation:

7 0
3 years ago
When 38.1 grams of a certain metal at a temperature of 90.0°C is added to 100.0mL of water at a temperature of 17.6°C in a perfe
MakcuM [25]

Answer:

a. qm = 627.3 J

b. qw = 627.3 J

c. C₂ = 227.4 J/kg.°C

Explanation:

a.

Since, the calorimeter is completely insulated. Therefore,

Heat Lost by Metal = Heat Gained by water

qm = qw

qm = m₁C₁ΔT₁

where,

qm = heat lost by metal = ?

m₁ = mass of water = (density)(volume) = (1000 kg/m³)(100 mL)(10⁻⁶ m³/1 mL)

m₁ = 0.1 kg

C₁ = specific heat capacity of water = 4182 J/kg.°C

ΔT₁ = Change in Temperature of Water = 19.1°C - 17.6°C = 1.5°C

Therefore,

qm = (0.1 kg)(4182 J/kg.°C)(1.5°C)

<u>qm = 627.3 J</u>

<u></u>

b.

Since,

qm = qw

<u>qw = 627.3 J</u>

<u></u>

c.

qm = m₂C₂ΔT₂

where,

m₂ = mass of metal = 38.1 g = 0.0381 kg

C₂ = specific heat capacity of metal = ?

ΔT₂ = Change in Temperature of metal = 90°C - 17.6°C = 72.4°C

Therefore,

627.3 J = (0.0381 kg)(C₂)(72.4°C)

(627.3 J)/(0.0381 kg)(72.4°C) = C₂

<u>C₂ = 227.4 J/kg.°C</u>

6 0
3 years ago
If 20 grams of aluminum react with 200 grams of bromide to form aluminum bromide and no aluminum is left after the reaction, but
Varvara68 [4.7K]
The answer is: 197 grams

Why?

All 20 grams of aluminum was used to form aluminum bromide. Only 177 grams of bromide were used to make aluminum bromide, since 23 grams were left over.

20 grams + 177 grams = 197 grams, so the answer is 197 grams.
8 0
4 years ago
An organism breathe with lungs lays eggs and has feathers the organism is?
NARA [144]
An organism that breathes with its lungs, lays eggs and has feathers is a bird!
4 0
4 years ago
Which has more mass, one mole of carbon (C) or one mole of copper (Cu)?<br> Explain.
inysia [295]
Carbon — pay attention to your periodic table trends
6 0
3 years ago
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