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Bad White [126]
3 years ago
13

what do the symbols tell you about the conditions of the reaction shown to the right check all boxes that apply

Chemistry
2 answers:
alukav5142 [94]3 years ago
6 0

Answer:

Sorry but erm was their supposed to be a image attach with it

Explanation:

Ugo [173]3 years ago
6 0

Answer: options 1 and 4

Explanation:

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An envelope could be a source of DNA evidence.<br><br> True<br><br> False
yuradex [85]

Answer:

True

Explanation:

DNA can be extracted from bite marks, cigarette buds, postage stamps on envelopes, and envelope flaps for DNA analysis.

7 0
2 years ago
Read 2 more answers
Find the grams in 1.26*10^-4 mol of HC2H3O2
Oksana_A [137]

Answer:

0.00757 grams

Explanation:

Find the molar mass of the compound: which is 60.05.

The molar mass is basically just the sum of all the atomic masses of each of the elements.

Then multiply the molar mass by the number of moles in the compound, which is 1.26 x 10^-4 moles.

Your answer should be 0.00757 grams.

5 0
3 years ago
QUICK QUESTION: On the Bohr model, how come potassium has 19 electrons in its valence shell if potassium has a K+? Isn’t it supp
Vlada [557]

Answer:  K only has 1 valence electron.  It will leave with only a little effort, leaving behind a positively charged K^+1 atom.

Explanation:  A neutral potassium atom has 19 total electrons.  But only 1 of them is in potassium's valence shell.  Valence shell means the outermost s and p orbitals.  Potasium's electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^6 4s^1.  The 4s orbital is the only orbital in the 4th energy level.  So it has a valency of 1.  This means this electron will be the most likely to leave, since it is the lone electron in the oyutermost energy level (4).  When that electron leaves, the charge on the atom go up by 1.  The atom now has a full valence shell of 3s^2 3p^6, the same as argon, Ar.

4 0
2 years ago
Question 9 of 10
aksik [14]

Answer:

The answer is B an open system allows energy and mass to move in and out of it

Hope it helps

7 0
2 years ago
A 4.36-g sample of an unknown alkali metal hydroxide is dissolved in 100.0 mL of water. An acid-base indicator is added, and the
BARSIC [14]

Answer:

Rb+

Explanation:

Since they are telling us that the equivalence point was reached after 17.0 mL of   2.5 M HCl were added , we can calculate the number of moles of HCl which neutralized our unknown hydroxide.

Now all the choices for the metal cation are monovalent, therefore the general formula for our unknown is XOH and  we know the reaction is 1 equivalent acid to 1 equivalent base. Thus we have the number of moles, n,  of XOH and from the relation n = M/MW we can calculate the molecular weight of XOH.

Thus our calculations are:

V = 17.0 mL x 1 L / 1000 mL = 0.017 L

2.5 M HCl x 0.017 L = 2.5 mol/ L x 0.017 L = 0.0425 mol

0.0425 mol = 4.36 g/ MW XOH

MW of XOH = (atomic weight of X + 16 + 1)

so solving the above equation we get:

0.0425 = 4.36 / (X + 17 )

0.7225 +0.0425X = 4.36

0.0425X = 4.36 -0.7225 = 3.6375

X = 3.6375/0.0425 = 85.59

The unknown alkali is Rb which has an atomic weight of 85.47 g/mol

6 0
3 years ago
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