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ioda
3 years ago
7

Znco3 has a molar mass of 125.40 g/mol. which of the conversion factors shown below correctly expresses this relationship as wel

l as the relationship between molar mass and the number of formula units of the compound? avogadro's number is 6.022 × 1023.
Chemistry
2 answers:
Naddika [18.5K]3 years ago
8 0

Answer:

the correct expression is 125.4 g ZnCO3 * 1 mol ZnCO3/6.022x10^23 formula units ZnCO3

Explanation:

The conversion factor that correctly expresses the relationship between the molar mass and the number of formula units of the compound is as follows.

Avogadro's number is defined as 6.022x10^23 particles/mole, therefore the conversion would be equal to:

125.4 g ZnCO3 * 1 mol ZnCO3/6.022x10^23 formula units ZnCO3

Airida [17]3 years ago
4 0
Answer : ZnCO_{3} will be 1 mole of ZnCO_{3} / 125. 40 g of ZnCO_{3}

Explanation : The molar mass and the formula units are the same thing in any compound so when given a molar mass of compound then one mole of that compound is divided by its molar mass. Where one mole will be equal to avogadro's number which is 6.022 X 10^{23}.
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Balance the following equation:<br> K+ H2O + H2 + KOH
alex41 [277]

Answer:

2K + 2H2O → H2 + 2KOH

Explanation:

Find how many atoms you have on both sides then add 2 to both sides.

Reactant:       Products:

K: 1+1=2                K: 1+1=2

H: 2+2=4             H: 3+1=4

O: 1+1=2                O: 1+1=2

Therefore it is balanced. Hope this helps

6 0
2 years ago
A chemist needs to make 250 mL of a 2.50 M aqueous solution of ammonium hydroxide from a 6.00 M ammonium hydroxide solution. How
Furkat [3]

Answer:

250 mL (total solution)  = 104 mL (stock solution)  + 146 mL (water)

Explanation:

Data Given

M1 = 6.00 M

M2 = 2.5 M

V1 = 250 mL

V2 = ?

Solution:

As the chemist needs to prepare 250 mL of solution from 6.00 M ammonium hydroxide solution to prepare a 2.50 M aqueous solution of ammonium hydroxide.

Now

first he have to determine the amount of ammonium hydroxide solution that will be taken from6.00 M ammonium hydroxide solution

For this Purpose we use the following formula

                    M1V1=M2V2

Put values from given data in the formula

                   6 x V1 = 2.5 x 250

Rearrange the equation

                   V1 = 2.5 x 250 /6

                    V1 = 104 mL

So 104 mL is the volume of the solution which we have to take from the 6.00 M ammonium hydroxide solution to prepare 2.5 M  aqueous solution of ammonium hydroxide

But we have to prepare 250 mL of the solution.

so the chemist will take 104 mL from 6.00 M ammonium hydroxide solution and have to add 146 mL water to make 250 mL of new solution.

in this question you have to tell about the amount of water that is 146 mL

250 mL (total solution)  = 104 mL (stock solution)  + 146 mL (water)

7 0
3 years ago
2. How many grams of water can be heated from 20.0 oC to 75oC using 12500.0 Joules?
kenny6666 [7]

Answer;

  = 0.054 kg or 54 g

Explanation;

Using the equation; Q = mcΔT where Q is the quantity of heat transferred, m is the mass, c is specific heat of the substance, ΔT is delta T, the change in temperature.  

ΔT = 75 - 20 = 55 C.  

Solve the equation for m  

m = Q/ cΔT

Mass = 12500 / (55 × 4200)

        = 0.054 kg or 54 g


4 0
3 years ago
Read 2 more answers
In two or more complete sentences explain how to balance the chemical equation and classify its reaction type.
Artemon [7]
<h3>Answer:</h3>

#1. Balanced equation: 2C₅H₅ + Fe → Fe(C₅H₅)₂

#2. Type of reaction: Synthesis reaction

<h3>Explanation:</h3>
  • Balanced equations are equations that obey the law of conservation of mass.
  • When an equation is balanced the number of atoms of each element is equal on both side of the equation.
  • Equations are balanced by putting appropriate coefficients on the reactants and products.
  • In our case, we are going to put coefficients 2, 1 and 1.
  • Thus, the balanced equation will be;

2C₅H₅ + Fe → Fe(C₅H₅)₂

  • This type of a reaction is known as synthesis reaction, in which two or more reactants or compounds combine to form a single compound or product.
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3 years ago
Need help on question 3 plz<br> URGENT HELP PLZ
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