<h2>
Question
</h2>
A sample of methane collected when the temp was 30 C and 760mmHg measures 398 mL. What would be the volume of the sample at -5 C and 616 mmHg pressure
<h2>
Answer:</h2>
434.32mL
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Explanation:</h2>
Using the combined gas law:
= k
Where;
P = Pressure
V = Volume
T = Temperature
k = constant.
It can be deduced that:
= 
= k ---------------------(i)
Where:
P₁ and P₂ are the initial and final pressures of the given gas
V₁ and V₂ are the initial and final volumes of the given gas
T₁ and T₂ are the initial and final temperatures of the gas.
<em>From the question:</em>
the gas is methane
P₁ = 760mmHg
P₂ = 616mmHg
V₁ = 398mL
V₂ = ?
T₁ = 30°C = (30 +273)K = 303K
T₂ = -5°C = (-5 +273)K = 268K
Substitute these values into equation (i) as follows;
= 
Solve for V₂
V₂ = 
V₂ = 434.32mL
Therefore, the volume of the sample at -5C and 616mmHg pressure is 434.32mL
Answer:
6
Explanation:
Li has an oxydation number of 1 2*1 = 2
O has an oxidation number of -2 4(-2) = -8
S has an oxydation number of x 1 * x = x
The oxidation number on the molecule is 0.
So here is the equation
2 - 8 + x = 0 Combine like terms
-6 + x = 0 Add 6 to both sides
-6 + 6 + x = 6 Combine like terms
x = 6
Sulphur in this case has an oxidation number of 6
The answer is b.gold can’t really explain but the answer is b.
you have to show us the rest of it because we have no idea what your looking at. I'm sorry
Answer:
C. Involves a metal and a nonmetal.
Explanation:
Ionic compound involves a metal and a non-metal. Ionic compounds have electrovalent bonds between them.
These compounds are usually made up of metals and non - metals combining to form a unit.
- The metals usually has low electronegativity and transfers it electrons to the non - metal.
- The non-metal has high affinity for the electron.
- The electrostatic attraction between the ions formed results in the ionic bond.
