1/2 x -41 x=10 Simplify the answer
1 answer:
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The solution to the Questions are
- The alternate hypothesis demonstrates that there are two possible outcomes for the test.
- Decision rule: If z > 2.05 or z<-2.05, reject H0
- z=2.59
- The two-tailed nature of the test is shown by the alternative hypothesis.
- The result of the test yields the following P-value: 0.0096
(a)
The alternate hypothesis demonstrates that there are two possible outcomes for the test.
(b)
Here we have
(b)
Here the test is two-tailed. So for , the critical values of the z-test are -2.05 and 2.05.
Decision rule: If z > 2.05 or z<-2.05, reject H0
(c)
Test statistics will be
z=2.59
(d)
The two-tailed nature of the test is shown by the alternative hypothesis.
(e)
The result of the test yields the following P-value: 0.0096
Read more about P-value
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Answer:
30.0
Step-by-step explanation:
Given our data is normally distribute with and
-Top 7% is given by find the z-value corresponding to p=(1-0.07)=0.93
-We substitute our values in the equation below;
Hence, the minimum score required for the scholarship is 30.0