Answer:
POTENTIAL ENERGY
A cup sitting on a table possesses potential energy
Explanation:
Answer Expert Verified
Answer:
Neon (Ne)
Hydrogen (H)
Argon (Ar)
Iron (Fe)
Calcium (Ca)
Deuterium, an isotope of hydrogen that has one proton and one neutron.
Plutonium (Pu)
F-, a fluorine anion.
Explanation:
I got u
Complete Question
The complete question is shown on the first uploaded image
Answer:
The concentration of
that should used originally is ![C_Z_o = 0.4492M](https://tex.z-dn.net/?f=C_Z_o%20%3D%200.4492M)
Explanation:
From the question we are told that
The necessary elementary step is
![2BC_2 ----->4C + B_2](https://tex.z-dn.net/?f=2BC_2%20-----%3E4C%20%2B%20B_2)
The time taken for sixth of 0.5 M of reactant to react ![t = 9 hr](https://tex.z-dn.net/?f=t%20%3D%209%20hr)
The time available is ![t_a = 3.5 hr](https://tex.z-dn.net/?f=t_a%20%3D%203.5%20hr)
The desired concentration to remain
Let Z be the reactant , Y be the first product and X the second product
Generally the elementary rate law is mathematically as
![-r_Z = kC_Z^2 = - \frac{d C_Z}{dt}](https://tex.z-dn.net/?f=-r_Z%20%3D%20kC_Z%5E2%20%3D%20-%20%5Cfrac%7Bd%20C_Z%7D%7Bdt%7D)
Where k is the rate constant ,
is the concentration of Z
From the elementary rate law we see that the reaction is second order (This because the concentration of the reactant is raised to power 2 )
For second order reaction
![\frac{1}{C_Z} - \frac{1}{C_Z_o} = kt](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BC_Z%7D%20%20-%20%5Cfrac%7B1%7D%7BC_Z_o%7D%20%20%3D%20kt)
Where
is the initial concentration of Z which a value of ![C_Z_o = 0.5M](https://tex.z-dn.net/?f=C_Z_o%20%3D%200.5M)
From the question we are told that it take 9 hours for the concentration of the reactant to become
![C_Z = C_Z_o - \frac{1}{6} C_Z_o](https://tex.z-dn.net/?f=C_Z%20%3D%20%20C_Z_o%20-%20%5Cfrac%7B1%7D%7B6%7D%20%20C_Z_o)
![C_Z = 0.5 - \frac{0.5}{6}](https://tex.z-dn.net/?f=C_Z%20%3D%200.5%20%20-%20%5Cfrac%7B0.5%7D%7B6%7D)
So
![\frac{1}{0.4167} - \frac{1}{0.50} = 9 k](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B0.4167%7D%20%20-%20%5Cfrac%7B1%7D%7B0.50%7D%20%20%3D%20%209%20k)
![0.400 = 9 k](https://tex.z-dn.net/?f=0.400%20%3D%209%20k)
=> ![k = 0.044\ L/ mol \cdot hr^{-1}](https://tex.z-dn.net/?f=k%20%3D%200.044%5C%20%20L%2F%20mol%20%5Ccdot%20hr%5E%7B-1%7D)
For ![C_Z = 0.42M](https://tex.z-dn.net/?f=C_Z%20%3D%200.42M)
![\frac{1}{0.42} - \frac{1}{C_Z_o} = 3.5 * 0.044](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B0.42%7D%20-%20%5Cfrac%7B1%7D%7BC_Z_o%7D%20%20%3D%203.5%20%2A%200.044)
![2.38 - 0.154 = \frac{1}{C_Z_o}](https://tex.z-dn.net/?f=2.38%20-%20%200.154%20%20%3D%20%20%20%20%5Cfrac%7B1%7D%7BC_Z_o%7D)
![2.226 = \frac{1}{C_Z_o}](https://tex.z-dn.net/?f=2.226%20%20%3D%20%20%20%20%5Cfrac%7B1%7D%7BC_Z_o%7D)
![C_Z_o = \frac{1}{2.226}](https://tex.z-dn.net/?f=C_Z_o%20%3D%20%5Cfrac%7B1%7D%7B2.226%7D)
![C_Z_o = 0.4492M](https://tex.z-dn.net/?f=C_Z_o%20%3D%200.4492M)
Answer:
The answer is
<h2>126.58 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
<h3>
![volume = \frac{mass}{density}](https://tex.z-dn.net/?f=volume%20%3D%20%20%5Cfrac%7Bmass%7D%7Bdensity%7D%20)
</h3>
From the question
mass of alcohol = 100 g
density = 0.79 g/mL
The volume is
![volume = \frac{100}{0.79} \\ = 126.58227848...](https://tex.z-dn.net/?f=volume%20%3D%20%20%5Cfrac%7B100%7D%7B0.79%7D%20%20%5C%5C%20%20%3D%20126.58227848...)
We have the final answer as
<h3>126.58 mL</h3>
Hope this helps you