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sdas [7]
3 years ago
14

A uniform plane wave traveling in air is incident upon a flat, lossless, and infinite in extent dielectric interface with a diel

ectric constant of 8. In the air medium, a standing wave is formed. If the normalized magnitude of the incident E-field is Eo = 1, determine the maximum value of the E-field standing wave pattern in air and the shortest distance l (in λo) from the interface where the first maximum in the E- field standing wave pattern will occur (normalized to the incident field). Select one: a. Maximum value of the E-field standing wave = 2.48; shortest distance l = λo/4 b. Maximum value of the E-field standing wave = 2.48; shortest distance l = λo/2 c. Maximum value of the E-field standing wave = 1.48; shortest distance l = λo/4 d. Maximum value of the E-field standing wave = 0.52; shortest distance l = λo/2

Physics
1 answer:
dexar [7]3 years ago
3 0

Answer:

Check the explanation

Explanation:

Kindly check the attached images below to see the step by step explanation to the question above.

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A stone with a weight of 5.29 N is launched vertically from ground level with an initial speed of 26.0 m/s, and the air drag on
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Answer:

a) 19.4 m/s

b) 19 m/s

Explanation:

a) In the given question,

the potential energy at the initial point = Ui = 0

the potential energy at the final point = Uf = mgh

the kinetic energy at the initial point = Ki = 1/2 mv₀².

the kinetic energy at the final point = Kf = 0

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Now, using the law of conservation of energy

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1/2 mv₀² + 0 = 0 + mgh + fh

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Read 2 more answers
A frog is at the bottom of a 17-foot well. Each time the frog leaps, it moves up 3 feet. If the frog has not reached the top of
docker41 [41]

Answer:

The frog takes 8 jumps to reach top of well

Explanation:

Given data

Frog at bottom=17 foot

Each time frog leaps 3 feet

Frog has not reached the top of the well, then the frog slides back 1 foot

To Find

Total number of leaps the frog needed to escape from well

Solution

in 1 jump distance jumped=3+(-1)

                                           =2 feet

                                           =2×1 feet

The "-1" is because the frog goes back

Now After 2 jumps the distance jumped as:

                     Distance Jumped=2+2

                     Distance Jumped=2*2

                                                   =4 feet

Similarly after 7 jumps

                    Distance Jumped=2+2+......+2

                    Distance Jumped=2*7

                                                 =14 feet

Now after 8th jump the frog climbs but doesnot slide back as it is reached to the top of well.

So

              Distance Jumped=(Distance Jumped after 7 jumps)+3

                                           =14+3

                                           =17 feet

The frog takes 8 jumps to reach top of well                

7 0
3 years ago
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