A uniform plane wave traveling in air is incident upon a flat, lossless, and infinite in extent dielectric interface with a diel
ectric constant of 8. In the air medium, a standing wave is formed. If the normalized magnitude of the incident E-field is Eo = 1, determine the maximum value of the E-field standing wave pattern in air and the shortest distance l (in λo) from the interface where the first maximum in the E- field standing wave pattern will occur (normalized to the incident field). Select one: a. Maximum value of the E-field standing wave = 2.48; shortest distance l = λo/4 b. Maximum value of the E-field standing wave = 2.48; shortest distance l = λo/2 c. Maximum value of the E-field standing wave = 1.48; shortest distance l = λo/4 d. Maximum value of the E-field standing wave = 0.52; shortest distance l = λo/2
1 answer:
You might be interested in
Answer:
The velocity of the hay bale is - 0.5 ft/s and the acceleration is
Solution:
As per the question:
Constant velocity of the horse in the horizontal,
Distance of the horse on the horizontal axis, x = 10 ft
Vertical distance, y = 20 ft
Now,
Apply Pythagoras theorem to find the length:
Now,
(1)
Differentiating equation (1) w.r.t 't':
where
= Rate of change of displacement along the horizontal
= Rate of change of displacement along the vertical
= velocity along the x-axis.
= velocity along the y-axis
Acceleration of the hay bale is given by the kinematic equation:
Answer:
According to the data given in the question, experiment on table two pulling and falling masses are arranged in the fig. 250 g is pulling right side and 100 g pulling down. The gravitational force is common to both the masses, so we cannot say that the block moves towards heavier mass, also the block does not move towards the lighter mass.
Obviously, the effect of heavier mass of 250 g is more on the block, so the block moves towards right bottom corner. i.e., diagonally between two masses
please find the attachment.
