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AveGali [126]
3 years ago
9

HELP ME PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!

Physics
1 answer:
soldi70 [24.7K]3 years ago
4 0
Limestone, Sandstone, and Shale would be the answer.

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2. Can you rearrange the equation F = kx to get k on one side of the equation
Bumek [7]

k = f/x

x = f/k

( / means divide )

5 0
3 years ago
The magnitude of the magnetic force on a current-carrying wire held in a magnetic
Kamila [148]

Answer:

All of the above

Explanation:

The magnitude of the magnetic force on a current-carrying wire held in a magnetic is given by the equation F = BIlsin \theta

Where B = Strength of the magnetic field

I = The current carried by the wire

l = length of the wire in the magnetic field

θ = Angle between the wire and the magnetic field

Based on the relationship written above, the magnitude of the magnetic force on the current - carrying wire in the magnetic field depends on the strength of the magnetic field (B), length of the wire(l), current in the wire (I).

All the options are correct.

3 0
3 years ago
Which model could represent a neutral atom of boron?
UNO [17]

Answer:

model 3

Explanation:

Boron with atomic number 5 will have 3 valence electrons

5 0
3 years ago
Read 2 more answers
If the engine receives 6.45 kJ of heat energy from the reservoir at 520 K in each cycle, how many joules per cycle does it rejec
Oxana [17]

Answer:

3.72 kJ

Explanation:

QH = 6.45 kJ

TH = 520 K

Tc = 300 K

Qc = ?

By use of Carnot's theorem

Qc / QH = Tc / TH

Qc / 6.45 = 300 / 520

Qc = 3.72 kJ

6 0
3 years ago
A ball of plasticine is released from rest at height of 2.2 m above the ground. After touching the ground, the plasticine ball c
Anna35 [415]

The magnitude of the acceleration of the ball while coming to rest is 477.43 m/s²

The direction of the acceleration of the ball is downwards

The given parameters

initial velocity of the ball, u = 0

height above the ground, h = 2.2 m

time of motion of the ball, t = 96 ms = 0.096 s

The magnitude of the acceleration of the ball while coming to rest is calculated as;

let the downwards direction of the acceleration be positive

h = ut + 0.5 at^2\\\\h = 0 + 0.5at^2\\\\h = 0.5 at^2\\\\a = \frac{h}{0.5t^2} \\\\a = \frac{2.2}{0.5 \times 0.096^2} \\\\a = 477.43 \ m/s^2

The direction of the acceleration of the ball is downwards

Learn more here: brainly.com/question/15407740

4 0
2 years ago
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