Answer:
(a) 2 (b) 4 (c) 4
Explanation:
Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.
Rules for significant figures:
- Digits from 1 to 9 are always significant and have infinite number of significant figures.
- All non-zero numbers are always significant. For example: 654, 6.54 and 65.4 all have three significant figures.
- All zero’s between integers are always significant. For example: 5005, 5.005 and 50.05 all have four significant figures.
- All zero’s preceding the first integers are never significant. For example: 0.0078 has two significant figures.
- All zero’s after the decimal point are always significant. For example: 4.500, 45.00 and 450.0 all have four significant figures.
- All zeroes used solely for spacing the decimal point are not significant. For example : 8000 has one significant figure.
As per question,
0.000054 has 2 significant figures.
3.001 x 10⁵ has 4 significant figures.
5.600 has 4 significant figures.
The Hubble Space Telescope is a joint ESA/NASA project and was launched in 1990 by the Space Shuttle mission STS-31 into a low-Earth orbit 569 km above the ground. During its lifetime Hubble has become one of the most important science projects ever. Hope this helps! ~ Autumn :)
Answer:
400.7886829 rad/s
Explanation:
First we have to turn our 0.35 rev/s into rad/s using the equation
(Xrev/s)*2pi=Xrad/s we can plug in .35*2pi=.7pi rad/s
Now we can us the equation m_1*v_1*r_1^2=m_1*v_2*r_2^2 we can plug in the given. Because the mass remains the same we can cross it off of both sides giving us just: v_1*r_1^2=v_2*r_2^2
(.7pi)*(.54)^2=(v_2)*(.04)^2
(.20412pi)=(v_2)*(.0016) [.20412pi=.6412618925]
then using division on both sides we get
(.6412618925/.0016)=v_2=400.79rad/s(This answer is rounded to the nearest hundreth)
See you in Mr.K's class tomorrow! -Ruben
Hi Pupil Here's Your Answer ::
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Pressure is defined as the force acting perpendicular on an unit area of the surface.
OR
The thrust per unit area is called Pressure.
let us see, on what factors the pressure depends?
Take a pin having a pointed end and a nail having blunt end. Press then against a cardboard by applying the same force. We find that the pin penetrates deep into the cardboard then the nail. In this case, force acting on two points of the cardboard is same but the area under the tip of the Pin is less than under the tip of the nail.
The effect of the forces of the scene magnitudes on the different area is different.
Conclusions : Pressure acting on the surface is inversely proportional to the area of the surface on which force acts.
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Hope this helps
