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harina [27]
3 years ago
15

The fast server in women's tennis is Venus Williams, who recorded a serve of 130   (209  ) in 2007.

Physics
1 answer:
Gemiola [76]3 years ago
7 0
Converting 209 km/hr to m/s:
209 km/hr = 58.0 m/s
Contact distance = 0.1 m

Using the equation of motion:
2as = v² - u², where initial velocity is 0

a = (58)² / (2 x 0.1)
a = 1.68 x 10⁴ m/s²
You might be interested in
At NASA's Zero Gravity Research Facility in Cleveland, Ohio, experimental payloads fall freely from rest in an evacuated vertica
Diano4ka-milaya [45]

Answer:

(a). Energy is 64,680 J

(b) velocity is 51.43m/s

(c) velocity in mph is 115.0mph

Explanation:

(a).

The potential energy P of the payload of mass m is at a vertical distance h is  

P =mgh.

Therefore, for the payload of mass m = 50kg at a vertical distance of h = 132 m, the potential energy is

P = (50kg)(9.8m/s^2)(132m)

\boxed{P = 64,680J}

(b).

When the payload reaches the bottom of the shaft, all of its potential energy is converted into its kinetic energy; therefore,

mgh= \dfrac{1}{2}mv^2

v= \sqrt{2gh}

v = \sqrt{2*9.8*135}

\boxed{v = 51.43m/s}

(c).

The velocity in mph is

\dfrac{51.43m}{s} * \dfrac{3600s}{hr} * \dfrac{1mile}{1609.34m}

\boxed{v= 115.0mph}

5 0
3 years ago
A car slowing down for a stop sign is an example of.....?
maxonik [38]
The answer would be D, negative acceleration
3 0
3 years ago
Read 2 more answers
The equation for gear ratio
Ymorist [56]
In a gear train with two gears, the gear ratio is defined as follows
R= \frac{\omega _A}{\omega _B} 

where \omega _A is the angular velocity of the input gear while \omega _B is the angular velocity of the output gear. 

This can be rewritten as a function of the number of teeth of the gears. In fact, the angular velocity of a gear is inversely proportional to the radius r of the gear:
\omega = \frac{v}{r}
But the radius is proportional to the number of teeth N of the gear. Therefore we can rewrite the gear ratio also as
R= \frac{\omega _A}{\omega _B} = \frac{r_B}{r_A} = \frac{N_B}{N_A}

4 0
3 years ago
Water flows from the bottom of a storage tank at a rate of r(t) = 300 − 6t liters per minute, where 0 ≤ t ≤ 50. Find the amount
SSSSS [86.1K]

r(t) models the water flow rate, so the total amount of water that has flowed out of the tank can be calculated by integrating r(t) with respect to time t on the interval t = [0, 35]min

∫r(t)dt, t = [0, 35]

= ∫(300-6t)dt, t = [0, 35]

= 300t-3t², t = [0, 35]

= 300(35) - 3(35)² - 300(0) + 3(0)²

= 6825 liters

7 0
3 years ago
A 878-kg (1940 lb) dragster, starting from rest, attains a speed of 25.9 m/s (57.9 mph) in 0.62 s. (a) Find the average accelera
salantis [7]

Answer:

41.8m/s^2

Explanation:

Since the dragster starts from rest, initial velocity (u) = 0m/s, final velocity (v) = 25.9m/s, time (t) = 0.62s

From the equations of motion, v = u + at

a = (v - u)/t = (25.9 - 0)/0.62 = 25.9/0.62 = 41.8m/s^2

7 0
2 years ago
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