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2 years ago

6

assuming there are no reflection of diliations explain how you would write the equation of the function whose is stretched graph

belowh

1 answer:

lesya692 [45]2 years ago

4 0

Answer:

Start with the parent function y=1/x^2

Add 3 to x in the denominator, because the graph is shifted left 3.

Add 1 to the fraction, because the graph is shifted up 1 unit

Step-by-step explanation:It is the answer 100% on assignment

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A gray crayon is made with 5\text{ mL}5 mL5, space, m, L of black wax for every 6\text{ mL}6 mL6, space, m, L of white wax.

zloy xaker [14]

The correct answers are B and C.

Since the mixture requires 5 mL of black wax and 6 mL of white wax, we want multiples of these numbers; specifically, we need multiples that are the same number of times away.

A does not work; 10 is 5*2 and 24 is 6*4. These won't be in the same ratio.

B works; 15 is 5*3 and 18 is 6*3. These have the same ratio.

C works; 35 is 5*7 and 42 is 6*7. These have the same ratio.

D does not work; 26 is not a multiple of 6.

E does not work; 45 is 5*9 and 48 is 6*8. These will not have the same ratio.

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3 years ago

Read 2 more answers

What is the measurement of angle X

jasenka [17]

I would say 60 degrees because the shape that has x is just a bigger version of the original so it would have the same angels so x is 60 degrees

3 0

3 years ago

**PLEASE HELP ASAP** Terri is analyzing a circle, y^2 + x^2 = 36, and a linear function g(x). Will they intersect?

Alborosie

We analyze the linear function to find that it has equation $y=x$ . Drawing the line, we find that it will intersect the circle at negative and positive x-coordinates.

We can prove this by substituting $y=x$ into the given equation:

$x^2+x^2=36$

$2x^2=36$

$x^2 = 18$

$x = \pm 3\sqrt{2}$

Hence, $x = 3\sqrt{2}$ or $-\sqrt{2}$ , so there are both positive and negative values for $x$ .

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3 years ago

Please help me ill give you 38 brainly

Naya [18.7K]

The answer is the first one

(with blue and orange triangles)

Dilation makes things bigger

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3 years ago

Can someone PLEASE help me with Trigonometry???

Svetach [21]

$\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\
-------------------------------\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2}
\\\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)
\\\\\\
\theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}$

but anyway, the numerator will give the angles, and θ is just half of each

$\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\
-------------------------------\\\\
sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}
\\\\\\
sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o
\\\\\\
\theta=\cfrac{-8.05}{2}\implies \theta=-4.025$

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there

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3 years ago