Answer:
d. The histogram would be approximately bell-shaped, and the normal quantile plot would have data points have follow a straight-line pattern.
Step-by-step explanation:
Since the variable is normally distributed, the histogram of women's height should be approximately bell shaped (if the data was obtained form a random sample).
Again, the variable is normally distributed, therefore, the quantile plot should follow a straight line pattern (a diagonal line to be more precise).
We can represent the base as z and the height as 2z+6. We are going to use the formula A=1/2*b*h and solve for z
180=1/2*z*(2z+6)
360=2z^2+6z
0=2z^2+6z-360
0=2(z^2+3z-180)
0=(z+15)(z-12)
So z=-15 and 12 but it must be positive so then the base is equal to 12
When we plug this into 2z+6 we get 30 for the height
2(12)+6=30
Hope this helps
Answer:
B
Step-by-step explanation:
observe
Distributive property
a(b+c)+ab+ac
a(b-c)=ab-ac
(6z^2-4z+1)(8-3z)
move for nicety
(8-3z)(6z^2-4z+1)
distribute
8(6z^2-4z+1)-3z(6z^2-4z+1)=
48z^2-32z+8-18z^3+12z^2-3z=
-18z^3+48z^2+12z^2-32z-3z+8=
-18z^3+60z-35z+8
Answer:
4
Step-by-step explanation:
I'm pretty sure theres a graph to this so....
The given parabolic graph of quadratic function
To find:What is F(6) for the quadratic function
Solution:We have given graph of quadratic function
there is a different value for Y and a different value for X
For f(6)
here X=6, need to find graph of quadratic function
X=6
f(6)=4
Y=4
Your welcome :)
