Answer:
The equilibrium position will shift towards the left hand side or reactants side
Explanation:
Decreasing the volume (increasing the pressure) of the system will shift the equilibrium position towards the lefthand side or reactants side. This is because, decreasing the volume (increasing the pressure) implies shifting the equilibrium position towards the side having the least number of moles.
There are two moles of reactants and a total of three moles of products(total). Hence decreasing the volume and increasing the pressure of the gas phase reaction will shift the equilibrium position towards the lefthand side.
Answer:
The pressure is 
Explanation:
From the question we are told that
The volume of the container is 
The mass of 
is 
The root-mean-square velocity is 
The root -mean square velocity is mathematically represented as
Now the ideal gas law is mathematically represented as
=> 
Where n is the number of moles which is mathematically represented as
Where M is the molar mass of
So
=> 
=> 
=> 
substituting values
=> 
=>
Aswer:
False, the values of the distance traveled and the displacement only coincide when the trayectorie is a straight line. Otherwise, the distance will always be greater than the offset.
Although these terms are used synonymously in other cases, they are totally different. Since the distance that a mobile travels is the equivalent of the length of its trajectory. Whereas, the displacement will be a vector magnitude.
<u>xXCherryCakeXx</u>.
The weight of the cooler is (mg). That's (26)(9.8) = 254.8 Newtons.
Its gravitational potential energy while it's up in the top row is (mgh). That's (254.8)(17.5) = 4,459 Joules.
That's how much work it took to get the cooler up to the top row, and that's the energy it gives up when it moves back down to the bench.
In order to bring it down . . .
-- Gravity does 4,459 joules of work on the cooler.
-- The team assistant does NEGATIVE 4,459 joules of work on it.
