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kow [346]
4 years ago
13

In coming to a stop, a car leaves skid marks 85m long on the highway. Assuming a deceleration of 3.0m/s/s , estimate the speed o

f the car just before braking.
Physics
1 answer:
muminat4 years ago
4 0
Based on your question where a car leaves skid marks 85m long on the highway nad getting to stop. The deceleration of the car is 3m/s^2 to estimate the speed of the car just before braking first is to analyze the problem then apply the necessary formulas. the possible answer is  510m/s
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Which of theses substances would be a poor conductor of electricity
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Answer:

B. Water and sugar.

Explanation:

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A Van de Graaff generator is one of the original particle accelerators and can be used to accelerate charged particles like prot
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595391.482946 m/s

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E = Energy = 1.85 keV

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Velocity of proton is given by

v=\sqrt{\dfrac{2E}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 1.85\times 10^3\times 1.6\times 10^{-19}}{1.67\times 10^{-27}}}\\\Rightarrow v=595391.482946\ m/s

The speed of the proton is 595391.482946 m/s

Current is given by

I=\dfrac{\Delta Q}{t}\\\Rightarrow \Delta Q=It\\\Rightarrow \Delta Q=5.15\times 10^{-3}\times (1\ sec)\\\Rightarrow Q=5.15\times 10^{-3}\ C

Number of protons is

n=\dfrac{Q}{e}\\\Rightarrow n=\dfrac{5.15\times 10^{-3}}{1.6\times 10^{-19}}\\\Rightarrow n=3.21875\times 10^{6}\ protons

The number of protons is 3.21875\times 10^{6}

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