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Whitepunk [10]
3 years ago
6

Determine the change in velocity of a car that start at rest and has a final velocity of 20 m/s north

Physics
1 answer:
romanna [79]3 years ago
6 0
The change in velocity is 20 m/s to the north.
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Two sides of a parallelogram are in the ratio 5 : 3. If its perimeter is 64 cm, find the lengths of its sides.​
Xelga [282]

Answer: 32

Explanation:

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3 years ago
What is the smallest, most basic level of organization in an animal or<br> plant?
Archy [21]

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hhmmmmmhmmmm hmhmmmm hmmm yeah i got nothing

Explanation:

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Two male moose charge at each other with the same speed and meet on a icy patch of tundra. As they collide, their antlers lock t
Ksenya-84 [330]
Change in velocity of larger moose: (1/3)v - v = -(2/3)v 
<span>change in velocity of small moose: (1/3)v - (-v) = (4/3)v </span>
<span>- (change in velocity of larger moose)/(change in velocity of smaller moose) = 2

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4 0
3 years ago
Read 2 more answers
A. How does increasing the voltage of a power supply in an electromagnet affect the strength of the magnetic field?
seropon [69]

PART A)

If we increase the voltage supply in an electromagnet then it will increase the current that is flowing in it

So here due to increase in current there will be increase in the magnetic field due to that electromagnet

PART B)

Here in electric generator the current is produced by rotating a coil between two strong magnets.

So here mechanical energy of rotation of coil is converted into electromagnetic energy.

PART C)

Step up transformer convert the lower voltage input into higher voltage output

here number of turns of coil in output side or secondary number of coils is more than the number of coils in primary side or input side

PART D)

Force on a moving charge is given by

F = q(\vec v \times \vec B)

here we know that

q = 0.000600 C

v = 2.8 \times 10^5 m/s

B = 4.21 T

now from above equation we have

F = 0.0006(2.8\times 10^5)(4.21)

F = 707.3 N

direction of force is given by right hand thumb rule

using that rule we got force downwards

7 0
2 years ago
Read 2 more answers
A particle of mass 10 g and charge 72 μC moves through a uniform magnetic field, in a region where the free-fall acceleration is
sineoko [7]

Answer:

-0.07163\hat k\ T or 0.07163 T into the page

Explanation:

m = Mass of particle = 10 g

a = Acceleration due to gravity = -9.8j m/s²

v = Velocity of particle = 19i km/s

q = Charge of particle = 72 μC

B = Magnetic field

Here the magnetic and gravitational forces on the particle are applied in the opposite direction so,

F_b=F_g

F_b=qvBsin\theta\\\Rightarrow F_b=qvBsin90\\\Rightarrow F_b=72\times 10^{-6}\times 19000B

F_g=ma\\\Rightarrow F_g=0.01\times -9.8

72\times 10^{-6}\times 19000B=0.01\times -9.8\\\Rightarrow B=\frac{0.01\times -9.8}{72\times 10^{-6}\times 19000}\\\Rightarrow B=-0.07163\hat k\ T

The magnetic field is 0.07163 T into the page

5 0
2 years ago
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