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zubka84 [21]
4 years ago
7

How to solve 2X^2+Y^2 = X^2-Y^2

Mathematics
1 answer:
arlik [135]4 years ago
5 0
   
2x^2+y^2 = x^2-y^2\\\\
2x^2 - x^2 + y^2 + y^2 = 0\\\\
x^2 + 2y^2=0\\\\
x^2 = 0~~~\Longrightarrow~~~\boxed{x=0}\\\\
2y^2 = 0~~~\Longrightarrow~~~y^2 = 0~~~\Longrightarrow~~~\boxed{y=0}\\\\





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PLEASE HELP ME IT'S DUE TODAY AND IT COULD HELP MY GRADE A LOT
ElenaW [278]

Answer:

c = 13

m∡A = 60°

m∡B = 30°

Step-by-step explanation:

This is a 5-12-13 triangle. However, to make sure, I will put the steps.

Allow for each sides to be denoted as a-b-c, in which c is the hypotenuse (longest side). Set the equation:

a² + b² = c²

Plug in the corresponding numbers to the corresponding variables:

5² + 12² = c²

Simplify. First, solve the exponents, and then add:

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√c² = √169

c = √169 = √(13 * 13) = 13

c = 13

13 is your answer for c.

Note the measurements of the angles. We know that this is a 30-60-90 triangle, and so it will be easy to figure it out. Note that the corresponding angles will depend on that of the opposite side's measurement lengths. The hypotenuse will always be on the opposite side of the largest angle (as given), as c, the longest side, is opposite of ∡C, which is the largest angle (90°). Based on this information, it means that ∡A would be 60° (as it is opposite of the middle number, 12), and ∡B would be 30° (opposite of the smallest number, 5).

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Answer: C
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So, he deposited 17 dollars, ( 4 ) 5 dollar bills, and 6 twenty dollar bills.

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He deposited a total of <u>157 dollars.</u>

hope this helps!

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3 years ago
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