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shepuryov [24]
3 years ago
12

Examples of applied force

Physics
2 answers:
Vladimir [108]3 years ago
4 0

Answer:

Push - The most common form of force is a push through physical contact (like a lawnmower or shopping cart)

Pull - You can apply a force by directly pulling on an object (like pulling a wagon)

Explanation:

dem82 [27]3 years ago
3 0

-- you sit on a chair

-- gravity pulls something down

-- water pushes a log up to float

-- air holds the skin of a balloon out, in a ball-shape

-- my dog bites a bone

-- air holds the tires of my car out, in donut shapes

-- a book presses on a table

-- my shoes press down on the floor

-- my feet press down on the bathroom scale

-- the bathroom scale presses up on my feet

-- gravity pulls the Earth up toward me

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A steam Rankine cycle operates between the pressure limits of 1500 psia in the boiler and 2 psia in the condenser. The turbine i
AlladinOne [14]

Answer:

a. Mass flow rate through the boiler = 5.462lbm/s

b. Power produced by the turbine = 2525.8kW

c. The rate of heat supply in the boiler = 6901.42Btu/s

d. Thermal efficiency of the cycle = 34.3%

Explanation:

In order to provide a solution, we must assume that ;

- The system is operating at a steady condition

- Kinetic and potential energy changes are negligible

Now from steam tables, we calculate specific volume v and enthalpy h as,

h_1 = 95.96Btu/lb (  h_1 = h_f at 2psia )

v_1 = 0.016238ft^3/lb ( v_1 = v_f at 2psia )

w_{p,in} = v_1(P_2-P_1) = 0.016238(1500-2) * \frac{1}{5.404} = 4.501 Btu/lb

w_p = h_2 - h_1\\h_2 = w_p+h_1=4.501+95.96=100.461Btu/lb

h_3 = 1364.0Btu/lb

s_3 = 1.5073Btu/lb.R

( at P_3 = 1500psia & T_3 = 800^0F )

P_4 = 2psia\\S_4 = S_3\\x_4S = \frac{S_4-S_f}{S_{fg}}=\frac{1.5073-0.1783}{1.7374}=0.765

( S_f & S_{fg} when pressure is 2psia)

h_4S = h_f+x_4S*h_{fg}=95.96+(0.765)(1021.0)=877.025Btu/lb

n_T= \frac{h_3-h_4}{h_3-h_4S}\\ h_4=h_3-n_T(h_3-h_4S)=1364.0-0.90(1364.0-877.025)=925.7Btu/lb

Therefore,

q_{in}=h_3-h_2=1364.0-100.461=1263.54Btu/lb\\q_{out}=h_4-h_1=925.7-95.96=829.74Btu/lb\\w_{net}=q_{in}-q_{out}=1263.54-829.74=433.8Btu/lb

To calculate the mass flow rate of steam in the cycle, we use the formula

W_{net}=mw_{net}\\m=\frac{W_{net}}{w_{net}} =\frac{2500}{433.8}=5.763*(\frac{0.94782Btu}{1Kj} )=5.462lb/s

where 1Kj = 0.947817 Btu

The power output and the rate of heat addition are calculated thus,

W_{T,out}=m(h_3-h_4)=(5.462lb/s)*(1364-925.7)Btu/lb*(\frac{1Kj}{0.94782Btu} )\\=5.462*438.3*1.055=2525.8KW

Q_{in}=mq_{in}=5.462(1263.54)=6901.46Btu/s

The thermal efficiency of the cycle can be found thus;

n_{th}=\frac{W_{net}}{Q_{in}} =\frac{2500}{6901.46}*(\frac{0.94782Btu}{1Kj} ) =0.343

= 34.3%

5 0
2 years ago
A piston uses 32 J of energy to do work as 68 J of heat are added to the cylinder of the piston. The change in internal energy o
enyata [817]
Internal energy<span> is defined as the </span>energy<span> associated with the random, disordered motion of molecules. It is denoted by U and  calculated by the expression:

</span>Δ<span>U = Q - W

We calculate as follows:

</span>ΔU = 68 J - 32 J
ΔU = 36 J
3 0
3 years ago
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The current through a certain heater wire is found to be fairly independent of its temperature. If the current through the heate
irina [24]

Answer:

(c) increase by a factor of four

Explanation:

energy = power x time, and power = resistance x current ^2. 2^2 = 4.

5 0
3 years ago
If i jump on a trampoline. is it an inelastic or elastic collision?
Sladkaya [172]
Inelastic Collision :P
5 0
3 years ago
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A physics student pushed a 50 kg load across the floor, accelerating it at a rate of 1.5 m/s . How much force did she apply?
garri49 [273]

Explanation:

if you're trying to find the acceleration then it's change in velocity ÷ time taken

4 0
2 years ago
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