The magnitude of the electric field for 60 cm is 6.49 × 10^5 N/C
R(radius of the solid sphere)=(60cm)( 1m /100cm)=0.6m

Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:

Substitute numerical values:

The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.
As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).
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Answer: For a total eclipse of the Sun to happen, the Moon must get directly in front of the Sun, as seen from Earth.
Explanation: solar eclipse occurs when something comes between the earth and the sun, casting it's shadow on the surface the earth. For the the sun to be blocked completely. The obstructing body must come directly between.
A. 75 ampere-turns
<u>Explanation:</u>
Given:
Number of turns, n = 50
Voltage, V = 9V
Current, I = 1.5A
MMF= ?
MMF is magnetomotive force.
MMF is independent on voltage and dependent on the number of turns and current in the wire.
Thus, MMF can be written as:

On substituting the value we get:
MMF = 50 X 1.5
MMF = 75 ampere-turns
It is important for people to learn physics so that they can better understand the basic laws of the universe, and most importantly, so we can look at things with common sense, for you my friend i recommend watching <em>mythbusters</em>, they teach physics and make learning fun they teach you to look at the world with common sense. hope i helped!!! have a good day.