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STatiana [176]
2 years ago
10

During the photoelectric effect experiment, a photon is emitted with 5.73 x10-20 J of kinetic energy. If the work function of th

e photosensitive surface is 0.540 eV, which is the frequency of the incident light? Show your work. (h = 6.626 x 10-34 J·s; 1 eV = 1.60 x 10-19 J)
Answer text
Physics
1 answer:
Lapatulllka [165]2 years ago
4 0

Answer:

Frequency of incident light = 995×10 12

Explanation:

hope this helped you :)

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A solar panel is used to recharge a battery. The solar panel produces 0.80 W of electrical power. The panel is 20% efficient. Wh
Vlad [161]

Answer:

Input power, Ip = 4 Watts

Explanation:

Given the following data;

Power output = 0.8 Watts

Efficiency = 20%

To find the power input of the sunlight onto the solar panel;

Mathematically, the efficiency of a machine is given by the formula;

Efficiency = \frac {Out-put \; power}{In-put \; power} * 100

Substituting into the formula, we have;

20 = \frac {0.8}{Ip} * 100

20 = \frac {80}{Ip}

Cross-multiplying, we have;

20Ip = 80

Ip = \frac {80}{20}

Input power, Ip = 4 Watts

8 0
3 years ago
What is conduction? Please help. First answer will mark Brainliest
Kruka [31]

Answer:

Conduction is the main method of thermal energy transfer in solids.

Hope this helps.....

7 0
4 years ago
Read 2 more answers
Bird bones have air pockets in them to reduce their weight—this also gives them an average density significantly less thanthat o
snow_tiger [21]

Answer:

41.4 g

41.4 cm³

1.08695 g/cm³

Explanation:

\rho = Density of water = 1 g/cm³

Mass of water displaced will be the difference of the

m=45-3.6\\\Rightarrow m=41.4\ g

Mass of water displaced is 41.4 g

Density is given by

\rho=\dfrac{m}{v}\\\Rightarrow v=\dfrac{m}{\rho}\\\Rightarrow v=\dfrac{41.4}{1}\\\Rightarrow v=41.4\ cm^3

So, volume of bone is 41.4 cm³

Average density of the bird is given by

\rho=\dfrac{45}{41.4}\\\Rightarrow \rho=1.08695\ g/cm^3

The average density is 1.08695 g/cm³

3 0
4 years ago
Beings on spherical asteroid have observed that a large rock is approaching their asteroid in a collision course. At 7514 km fro
luda_lava [24]

Answer:

c. 4.582\times10^{21} kg

Explanation:

r_{i} = Initial distance between asteroid and rock = 7514 km = 7514000 m

r_{f} = Final distance between asteroid and rock = 2823 km = 2823000 m

v_{i} = Initial speed of rock = 136 ms⁻¹

v_{f} = Final speed of rock = 392 ms⁻¹

m = mass of the rock

M = mass of the asteroid

Using conservation of energy

Initial Kinetic energy of rock + Initial gravitational potential energy = Final Kinetic energy of rock + Final gravitational potential energy

(0.5) m v_{i}^{2} - \frac{GMm}{r_{i}} = (0.5) m v_{f}^{2} - \frac{GMm}{r_{f}} \\(0.5) v_{i}^{2} - \frac{GM}{r_{i}} = (0.5) v_{f}^{2} - \frac{GM}{r_{f}} \\(0.5) (136)^{2} - \frac{(6.67\times10^{-11}) M}{(7514000)} = (0.5) (392)^{2} - \frac{(6.67\times10^{-11}) M}{(2823000)} \\M = 4.582\times10^{21} kg

8 0
4 years ago
A diver who weighs 500 N steps off a diving board that is 10 m above the water. The diver hits the water with kinetic energy of_
Ksju [112]

Answer:

Diver hits the water with kinetic energy of 5000 J

Explanation:

We have given weight of the diver F = 500 N

Diver steps off a diving board which is 10 m above the water

So work don by diver W=force\times distance=500\times 10=5000J

Now according to energy theorem work done is equal to kinetic energy

So kinetic energy will be equal to 5000 J

So diver hits the water with kinetic energy of 5000 J

6 0
3 years ago
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