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STatiana [176]
2 years ago
10

During the photoelectric effect experiment, a photon is emitted with 5.73 x10-20 J of kinetic energy. If the work function of th

e photosensitive surface is 0.540 eV, which is the frequency of the incident light? Show your work. (h = 6.626 x 10-34 J·s; 1 eV = 1.60 x 10-19 J)
Answer text
Physics
1 answer:
Lapatulllka [165]2 years ago
4 0

Answer:

Frequency of incident light = 995×10 12

Explanation:

hope this helped you :)

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In the woman's mouth if
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Answer:

hi mate,

interesting question, first of all the pressure is determined by using the following formula:

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hope it helps, :-)

please mark me as brainliest

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