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Charra [1.4K]
3 years ago
7

A baseball player throws a baseball with a velocity of 13 m/s north. It is caught by a second player seven seconds later. How fa

r is the second player from the first player?
A. 91 meters north
B. 91 meters south
C. 91 meters east
D. 91 meters west
Physics
1 answer:
guajiro [1.7K]3 years ago
7 0

Answer:

A. 91 meters north

Explanation:

Take +y to be north.

Given:

v₀ = 13 m/s

a = 0 m/s²

t = 7 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (13 m/s) (7 s) + ½ (0 m/s²) (7 s)²

Δy = 91 m

The displacement is 91 m north.

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