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Charra [1.4K]
3 years ago
7

A baseball player throws a baseball with a velocity of 13 m/s north. It is caught by a second player seven seconds later. How fa

r is the second player from the first player?
A. 91 meters north
B. 91 meters south
C. 91 meters east
D. 91 meters west
Physics
1 answer:
guajiro [1.7K]3 years ago
7 0

Answer:

A. 91 meters north

Explanation:

Take +y to be north.

Given:

v₀ = 13 m/s

a = 0 m/s²

t = 7 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (13 m/s) (7 s) + ½ (0 m/s²) (7 s)²

Δy = 91 m

The displacement is 91 m north.

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Read 2 more answers
(a) What is the current involved when a truck battery sets in motion 720 C of charge in 4.00 s while starting an engine? (b) How
OLEGan [10]

Answer:

(a) Current flowing through truck battery is 180 A

(b) Time taken in calculator is 333.33 s

Explanation:

(a) Given:

The charge on the truck battery,q = 720 C

Time, t = 4.00 s

Consider I be the current flowing through truck battery.

The relation between current, charge and time is:

I = q/t

Substitute the suitable values in the above equation.

I=\frac{720}{4}

I = 180 A

(b) Given:

The charge on the calculator,q = 7.00 C

The current flowing through calculator, I = 0.3 mA = 0.3 x 10⁻³ A

Consider t be the time.

The relation between current, charge and time is:

t = q/I

Substitute the suitable values in the above equation.

t=\frac{1}{0.3\times10^{-3} }

I = 333.33 s

8 0
4 years ago
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