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Charra [1.4K]
2 years ago
7

A baseball player throws a baseball with a velocity of 13 m/s north. It is caught by a second player seven seconds later. How fa

r is the second player from the first player?
A. 91 meters north
B. 91 meters south
C. 91 meters east
D. 91 meters west
Physics
1 answer:
guajiro [1.7K]2 years ago
7 0

Answer:

A. 91 meters north

Explanation:

Take +y to be north.

Given:

v₀ = 13 m/s

a = 0 m/s²

t = 7 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (13 m/s) (7 s) + ½ (0 m/s²) (7 s)²

Δy = 91 m

The displacement is 91 m north.

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The answer is:  " 208 g " .
_____________________________________________
Explanation:
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The formula/ equation for density is:
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                   "mass per unit volume";  in which the "mass" is expressed in units of "g" ("grams") ;  and the "unit volume" is expressed in units of:
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   in which:

     "D" refers to the "density" (see above), which is: "8.9 g/cm³ " (given); 

     "m" refers to the "mass" , in units of "g" (grams), which is unknown; and we want to find this value;
                 
     "V" refers to the "volume", in units of "cm³ " ;
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                 We want to find the mass, "m" ; so we take the original equation/formula for the density:
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              D  =  m / V ; 
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             And we rearrange; to isolate "m" (mass) on ONE side of the    equation; and then we plug in our known/given values;
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    Multiply each side of the equation by "V" ; 
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             V * { D  =  m / V } ;  to get:
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      V * D = m ;   ↔   m = V * D ;
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           Now, we plug in the given values for "V" (volume) and "D" (density) ;     to solve for the mass, "m" ;
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 →  Round to "208 g" (3 significant figures);  
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The answer is:  " 208 g " .
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