Answer:
the point between Earth and the Moon where the gravitational pulls of Earth and Moon are equal is <em>E)3.45 × 10⁸ m</em>
Explanation:
The force that the Earth exerts on a mass m is
F_e = (G M_e m) / R_e²
where
- G is the universal gravitational constant
- M_e is the mass of Earth
- R_e is the radius of Earth
The force that the Moon exerts on a mass m is
F_m = (G M_m m) / R_m²
where
- G is the universal gravitational constant
- M_m is the mass of the Moon
- R_m is the radius of the Moon
Therefore, the point where the gravitational pulls of Earth and Moon are equal is:
F_e = F_m
R_e + R_m = R = 3.84×10⁸ m
Thus,
(G M_e m) / R_e² = (G M_m m) / R_m²
M_e / R_e² = M_m / (R - R_e²)
(R - R_e²) / R_e² = M_m / M_e
(R - R_e) / R_e = (M_m / M_e)^1/2
R_e(R/R_e -1) / R_e = (M_m / M_e)^1/2
R/ R_e = (M_m / M_e)^1/2 + 1
R_e = R / [(M_m / M_e)^1/2 + 1]
R_e = (3.84×10⁸ m) / [(7.35 x 10²² kg / 5.97 x 10²⁴ kg )^1/2 + 1]
R_e = 3.45 × 10⁸ m
Therefore, the point between Earth and the Moon where the gravitational pulls of Earth and Moon are equal is <em>3.45 × 10⁸ m.</em>
You’d do 23 x 3.5 which equals 80.5 miles, she traveled 80.5miles
2 because you would subtract 7 kilometers from 5 kilometers. And you would get 2 as your DP (displacement).
To attain equilibrium there should be net force on the body, so that the object will not be in motion. so for a body of wb, any weight will do as long as there is no external force that is applied to it. the only force that is acting on it is the weight which is going down, and the normal force which is going up, to counter act the weight. and the net force is zero.
Answer:
D.
R increases
V is constant
I decreases
Explanation:
The resistance of a wire is given by the following formula:
It is clear from this formula that resistance is directly proportional to the length of wire. So, when length of wire is increased, <u>the resistance of circuit increases</u>.
The <u>voltage in the circuit will be constant</u> as the voltage source remains same and it is not changed.
Now, we can use Ohm Law:
V = IR
at constant V:
I ∝ 1/R
it means that current is inversely proportional to resistance. Hence, the increase of resistance causes <u>the current in circuit to decrease.</u>
Therefore, the correct option will be:
<u>D.</u>
<u>R increases
</u>
<u>V is constant
</u>
<u>I decreases</u>