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Anvisha [2.4K]
3 years ago
6

How many moles are present in 1.75 g of zinc sulfate, Znso, ?

Chemistry
1 answer:
Cerrena [4.2K]3 years ago
7 0

Explanation:

We assume you are converting between grams ZnSO4 and mole. You can view more details on each measurement unit: molecular weight of ZnSO4 or mol This compound is also known as Zinc Sulfate. The SI base unit for amount of substance is the mole. 1 grams ZnSO4 is equal to 0.0061941519772353 mole.

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Is CO2 a covalent or ionic bond? will give brainliest for the correct answer​
NeX [460]

Answer:

covalent bond

Explanation:

a covalent bond happens between two nonmetals

a ionic bond happens between a metal and a non metal

CO2 is a bond between carbon and oxygen

carbon and oxygen are both non metals therefore CO2 is a covalent bond

4 0
2 years ago
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In order for a process to be spontaneous, Multiple Choice the entropy of the surroundings must increase. the entropy of the surr
Crazy boy [7]

Answer:

The correct answer is entropy change of the surrounding plus the entropy change of the system must be positive.

Explanation:

The term entropy is a state function.Entropy can be defined as the disorder or randomness of the molecules in a system.

 A spontaneous reaction is a type of reaction which deals with the release of free energy.The change of free energy in case of spontaneous reaction is always negative.

 According to the second law of thermodynamics a spontaneous reaction will occur in a system if the total entropy of both  system and surrounding increases during the reaction.

8 0
3 years ago
Rick has taken a loan of $3,200 from the bank to buy new appliances. His first loan payment is due at the end of this month. He
marysya [2.9K]

Answer:

140

Explanation:

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3 years ago
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Please help!! I have 10 minutes left!!
Licemer1 [7]

Explanation:

1 is a process that occurs when gases in earth's atmosphere trap the sun's heat .

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8 0
3 years ago
A gas is collected in a 34.3L container at a temperature of 31.5°C. Later, the container has a volume of 29.2L, a temperature of
goldenfox [79]

Answer:

108 kPa  

Step-by-step explanation:

To solve this problem, we can use the <em>Combined Gas Laws</em>:

p₁V₁/T₁ = p₂V₂/T₂             Multiply each side by T₁

   p₁V₁ = p₂V₂ × T₁/T₂      Divide each side by V₁

      p₁ = p₂ × V₂/V₁ × T₁/T₂

Data:

p₁ = ?;                 V₁ = 34.3 L; T₁ = 31.5 °C

p₂ = 122.2 kPa; V₂ = 29.2 L; T₂ = 21.0 °C

Calculations:

(a) Convert temperatures to <em>kelvins </em>

T₁ = (31.5 + 273.15) K = 304.65 K

T₂ = (21.0 + 273.15) K = 294.15 K

(b) Calculate the <em>pressure </em>

p₁ = 122.2 kPa × (29.2/34.3) × (304.65/294.15)  

   = 122.2 kPa × 0.8542 × 1.0357

   = 108 kPa

4 0
3 years ago
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