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3 years ago

How many moles are present in 1.75 g of zinc sulfate, Znso, ?

Chemistry

1 answer:

Cerrena [4.2K]3 years ago

7 0

Explanation:

We assume you are converting between grams ZnSO4 and mole. You can view more details on each measurement unit: molecular weight of ZnSO4 or mol This compound is also known as Zinc Sulfate. The SI base unit for amount of substance is the mole. 1 grams ZnSO4 is equal to 0.0061941519772353 mole.

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3 years ago

A block of dry ice (-40°C) is placed in contact with an ice cube (-10°C).

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Explanation:

Answer is that : no heat will flow

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3 years ago

A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of

Scilla [17]

Answer:

The essence including its given problem is outlined in the following segment on the context..

Explanation:

The given values are:

Moles of CO₂,

x = 0.01962

Moles of water,

$\frac{y}{2} =0.01961$

$y=2\times 0.01961$

$=0.03922$

Compound's mass,

= 0.4647 g

Let the compound's formula will be:

$C_{x}H_{y}O_{z}$

Combustion's general equation will be:

⇒ $C_{x}H_{y}O_{z}+x+(\frac{y}{4}-\frac{z}{2}) O_{2}=xCO_{2}+\frac{y}{2H_{2}O}$

On putting the estimated values, we get

⇒ $12\times x=1\times y+16\times z=0.4647$

⇒ $12\times 0.01962+1\times 0.03922+16\times z=0.4647$

⇒ $0.27466+16z=0.4647$

⇒ $z=0.01187$

Now,

x : y : z = $0.01962:0.03922:0.01187$

= $\frac{0.01962}{0.0118}:\frac{0.03922}{0.0188}:\frac{0.0188}{0.0188}$

= $1.6:3.3:1.0$

= $3:6:2$

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3 years ago

Will mark brainliest

MArishka [77]

Answer:

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3 years ago

A chemist must dilute 34.3mL of 1.72mM aqueous calcium sulfate solution until the concentration falls to 1.00mM. He'll do this b

EastWind [94]

Answer:

58.9mL

Explanation:

Given parameters:

Initial volume = 34.3mL = 0.0343dm³

Initial concentration = 1.72mM = 1.72 x 10⁻³moldm⁻³

Final concentration = 1.00mM = 1 x 10⁻³ moldm⁻³

Unknown:

Final volume =?

Solution:

Often times, the concentration of a standard solution may have to be diluted to a lower one by adding distilled water. To find the find the final volume, we must recognize that the number of moles of the substance in initial and final solutions are the same.

Therefore;

C₁V₁ = C₂V₂

where C and V are concentration and 1 and 2 are initial and final states.

now input the variables;

1.72 x 10⁻³ x 0.0343 = 1 x 10⁻³ x V₂

V₂ = 0.0589dm³ = 58.9mL

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3 years ago