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Sonbull [250]
1 year ago
10

a solution with a transmittance of 0.44 is analyzed in a spectrophotometer with 6% stray light. calculate the absorbance reporte

d by this defective instrument.
Chemistry
1 answer:
IgorLugansk [536]1 year ago
3 0

The absorbance reported by the defective instrument was 0.3933.

Absorbance A = - log₁₀ T

Tm = transmittance measured by spectrophotometer

Tm = 0.44

Absorbance reported in this equipment = -log₁₀ (0.44) = 0.35654

True absorbance can be calculated by true transmittance, Tm = T+S(α-T)

S = fraction of stray light = 6%= 6/100 = 0.06

α= 1, ideal case

T = true transmittance of the sample

Tm = T+S(α-T)

now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233

therefore, actual reading measured is A = -log₁₀ T = -log₁₀ (0.404233)

i.e; 0.3933

To know more about transmittance click here:

brainly.com/question/17088180

#SPJ4

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C. United States, Russia, and China

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2 years ago
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Explanation:

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3 years ago
A sample of 8.5 g NH 3 on oxidation produces 4.5 g of NO. Calculate the percent yield.
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3 years ago
Indicate what happens to the concentration of Pb2+ in each half cell
Taya2010 [7]

Answer:

Your questions requires diagrams of the cell to get which one is on the left or right. However, see the attached file below

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In the Left Beaker (Left half cell), their is less concentration

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<h3>Further explanation</h3>

Given

Reaction and the enthalpy

Required

the enthalpy

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Hess Law

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