Answer:
690 g IrI₃
Explanation:
To convert from moles to grams, you have to use the molar mass of the compound. The molar mass of IrI₃ is 572.92 g/mol. You use this as the unit converter in this equation:
Round to the lowest number of significant figures which is 2 to get 690 g IrI₃.
The total atomic number must be the same on each side. The total mass number must be the same on both side.
<span>On the RHS, for the mass number, we have 257 + 4 = 261 (the 4 comes from the 4 neutrons). That means the mass number of the missing piece on the LHS is 261 - 247 = 14. </span>
<span>One the RHS, for the atomic number we have a total of 104 since the 4 neutrons are all neutral. On the LHS, we have this: 104 - 98 = 6. </span>
<span>The missing piece is a nucleus of carbon 14. Done in your style, it is 14/6C</span>
https://mgdic.files.wordpress.com/2016/12/unit-operations.pdf this
0.97 g/ml
Since 1000cm³ = 1 litre. And 1ml = 10^-3 l = 10^-3 * 1000 cm³ = 1cm³
0.97 g/ml = 0.97 g/cm³
And since it is less than density of water which is 1.00 g/cm³. The object will rest on the water.
It will not float. It will float if its density is equal to density of water, and would sink if its density is greater than that of water and would rest on the water if its density is less than that of water.
