So 400,000 DVD sales with a 31% decline means in the 1st year following, there will be a decline of 124,000 DVDs sold. So we need to take 400,000 - 124,000, which equals a starting point for year two is 276,000 DVDs.
So a 31% decline on 276,000 = 85,560. So we need to subtract that from 85,560 from 276,000 which is 190,440. So at the end of the second year, DVD sales were only 190,440. That's also out starting point of the 3rd year.
So 31% of 190,440 equals 59,036.4 for the third year of DVD sales. So we need to subtract 59,036.4 from out third year starting point of 190,440, which equals 131,403.6, but since you can't have parts of DVDs, we'll round the decimal point fraction to a whole number to end up with 131,404 DVDs sold in year three.
So after three years of a 31% yearly decline in DVD sales you end up with DVD sales are 131,404
3/9 because it is the same as 1/3 or 2/6.
Answer:
-3/2
Step-by-step explanation:
Given two points, we can find the slope by
m = (y2-y1)/(x2-x1)
= (-7 - -1)/ (5-1)
= (-7+1)/(5-1)
= -6/4
= -3/2
Answer:
The perimeter and area of the square are 56 units and 196 square units, respectively.
Step-by-step explanation:
The inner right triangle represents a 45-45-90 right triangle, which has the feature of a hypotenuse whose length is 
time the length of any of its legs. If the hypotenuse has a measure of 
, then the legs of the triangle have a measure of 
.
Now, we are aware that the side length of the square is twice the length of the leg of the right triangle. Then, side length of the square is 14 units long.
Lastly, we know from Geometry that the perimeter and area of the square are represented by the following expressions:
Perimeter
(1)
Area
(2)
Where 
is the side length of the square.
If we know that 
, then the perimeter and area of the square are, respectively:
The perimeter and area of the square are 56 units and 196 square units, respectively.
The vertex U' is located at (-4, -5)
<h3>How to determine the location of U'?</h3>
The vertices are given as:
U = (-4, 5)
V = (-6, 2)
The rule of transformation is given as:
Reflection across the x-axis
This is represented as:
(x, y) => (x, -y)
So, we have:
U' = (-4, -5)
Hence, the vertex U' is located at (-4, -5)
Read more about transformation at:
brainly.com/question/11707700
#SPJ1
<u>Complete question</u>
Quadrilateral UVWX is reflected over the x-axis to form quadrilateral U′V′W′X′. If vertex U is located at (-4, 5) and vertex V is located at (-6, 2), then vertex U′ is located at
