X^4 + x^3 + x^2 + x = 0
x(x^3 + x^2 + x + 1) = 0
x[x^2(x + 1) + 1(x + 1)] = 0
x(x + 1)(x^2 + 1) = 0 ⇔ x = 0 or x + 1 = 0 or x^2 + 1 = 0
x = 0 or x = -1 or x^2 = -1 -false
Answer: x= 0 or x = -1.
First we will do -3 times everything in the parenthesis.
-3 times -4n = 12n
-3 times 30 = -90
SO,
12n - 90 = -30
+90 +90
12n = 60
divide 12 on both sides;
n = 5
This is your answer,
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Answer:
x = 12, y = 0
Step-by-step explanation:
Use elimination.
24y = 0
y = 0
Then plug back into the second equation.
2x + 9(0) = 24
2x = 24
x = 12
Plug back into the first equation to check.
Answer:
1. Given
2. Distributive property
4. Division property
Step-by-step explanation: