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Strike441 [17]
3 years ago
7

Can someone help me with 23,24, and25 please there a little confusing

Mathematics
1 answer:
cricket20 [7]3 years ago
8 0

Step-by-step explanation:

23)\\\\-14\leq\dfrac{x}{10}\qquad\text{multiply both sides by 10}\\\\(10)(-14)\leq10\!\!\!\!\!\diagup^1\cdot\dfrac{x}{10\!\!\!\!\!\diagup_1}\\\\-140\leq x\to x\geq-140\\\\24)\\-20

=============================

<, > - open circle

≤, ≥ - closed circle

<, ≤ - draw a line to the left

>, ≥ - draw a line to the right

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Which one is greater 2/3 or 4/5
Reptile [31]

2/3 because it’s out of 3, if you cut a pizza in 3 slices the slices are bigger and if u take 2 out of the three the remaining piece is bigger than the 4/5 because those 5 pieces will be cut smaller

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X/2 + 3/2 &lt; 5/2 give solution ​
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Start with

\dfrac{x}{2}+\dfrac{3}{2}

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A sample of salary offers (in thousands of dollars) given to management majors is: 48, 51, 46, 52, 47, 48, 47, 50, 51, and 59. U
balu736 [363]

Answer:

Step-by-step explanation:

number of samples, n = 10

Mean = (48 + 51 + 46 + 52 + 47 + 48 + 47 + 50 + 51 + 59)/10 = 49.9

Standard deviation = √(summation(x - mean)/n

Summation(x - mean) = (48 - 49.9)^2 + (51 - 49.9)^2 + (46 - 49.9)^2+ (52 - 49.9)^2 + (47 - 49.9)^2 + (48 - 49.9)^2 + (47 - 49.9)^2 + (50 - 49.9)^2 + (51 - 49.9)^2 + (59- 49.9)^2 = 128.9

Standard deviation = √128.9/10 = 3.59

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

Where

s = sample standard deviation

From the information given, the population standard deviation is unknown and the sample size is small, hence, we would use the t distribution to find the z score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 10 - 1 = 9

Since confidence level = 95% = 0.95, α = 1 - CL = 1 – 0.95 = 0.05

α/2 = 0.05/2 = 0.025

the area to the right of z0.025 is 0.025 and the area to the left of z0.025 is 1 - 0.025 = 0.975

Looking at the t distribution table,

z = 2.262

Margin of error = 2.262 × 3.59/√10

= 2.57

the lower limit of this confidence interval is

49.9 - 2.57 = 47.33

the lower limit of this confidence interval is

49.9 + 2.57 = 52.47

So it is false

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3 years ago
Find the Area of the figure below, composed of a rectangle and one semicircle, with another semicircle removed. Round to the nea
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Answer:

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