1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vsevolod [243]
2 years ago
13

Donde se pueden encontrar un río biejo​

Chemistry
1 answer:
larisa86 [58]2 years ago
6 0

Answer:

Puerto Rico

Explanation:

You might be interested in
What is the relationship between mass and the end stages of stars
aleksandr82 [10.1K]
The mass of stars affect how they end. 

Stars with greater mass sometimes end with supernovas, a giant explosion, which can result in black holes or neutron stars, or sometimes nothing.

A medium sized star can result in a planetary nebula, which then results in a white dwarf.

Haha hope this sorta helped :)


6 0
3 years ago
Will
Sedaia [141]
Wait whAttt I dont get this at all
6 0
3 years ago
For which of the following materials is necessary to stop a beta particle?
tensa zangetsu [6.8K]
Hello.

The answer would be <span>A. Three feet of concrete.

Have a nice day.</span>
8 0
2 years ago
You have 500.0 ml of a buffer solution containing 0.30 m acetic acid (ch3cooh) and 0.20 m sodium acetate (ch3coona). what will t
Nataly [62]
First, we should get moles acetic acid = molarity * volume

                                                                =0.3 M * 0.5 L

                                                                =  0.15 mol

then, we should get moles acetate = molarity * volume

                                                           = 0.2 M * 0.5L

                                                           = 0.1 mol

then, we have to get moles of OH- which added:

moles OH- = molarity  * volume

                   = 1 M    * 0.02L

                  = 0.02 mol

when the reaction equation is:


                 CH3COOH  +  OH-  → CH3COO-   +  H2O


moles acetic acid after adding OH- = (0.15-0.02) 
                                             
                                                            =  0.13M                                       

moles acetate after adding OH- =  (0.1 + 0.02)

                                                      =   0.12 M

Total volume = 0.5 L + 0.02 L= 0.52 L

∴[acetic acid] = moles acetic acid after adding OH- / total volume

                        = 0.13mol / 0.52L

                       = 0.25 M

and [acetate ) = 0.12 mol / 0.52L
 
                        = 0.23 M

by using H-H equation we can get PH:

PH = Pka + ㏒[salt/acid]

when we have Ka = 1.8 x 10^-5

∴Pka = -㏒Ka 

        = -㏒ 1.8 x 10^-5

       = 4.7

So by substitution:

∴ PH = 4.7 + ㏒[acetate/acetic acid]

         = 4.7 + ㏒(0.23/0.25)

        = 4.66
6 0
2 years ago
Which sequence contains elements listed from most reactive to least reactive? *
Helga [31]

Answer:

Reactivity Series

Explanation:

Potassium

Sodium

Lithium

Calcium

Magnesium

Aluminium

Zinc

Iron

Copper

Silver

Gold

7 0
2 years ago
Other questions:
  • How to know if you can heat a laboratory flask and other glassware?
    7·1 answer
  • 1) Which statement describes the relationship between thermal energy and particle movement?
    14·1 answer
  • A beaker contains a mixture of sand and small pebbles. what kind of mixture is this?
    13·1 answer
  • Ill give u brainliest and all my points! pls help
    9·1 answer
  • Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
    11·1 answer
  • Density is calculated by solving for a mass divided by ______
    6·1 answer
  • Which is the limiting reactant if we start with 30.0 g Al and 30.0 h O2​
    7·1 answer
  • What is the chemistry of acid and base
    12·1 answer
  • Plz someone help, really struggling
    9·1 answer
  • Give the systematic names for the formulas or give the formulas for the names:
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!