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Vaselesa [24]
3 years ago
15

If a solution of HCI has a molarity of 2.70M and a volume of 1.20L, what was the initial molarity if the initial volume was 0.50

0L?
O 6.4M
O 3.24M
O 1.13M
O 6.48M
+
Chemistry
1 answer:
erastovalidia [21]3 years ago
5 0

Answer:

6.48 M

Explanation:

M₁V₁ = M₂V₂

Step 1: Define

Molarity₁ = 2.70 M

Volume₁ = 1.20 L

Molarity₂ = unknown

Volume₂ = 0.500 L

Step 2: Substitute and Evaluate for M₂

(2.70 M)(1.20 L) = (M₂)(0.500 L)

3.24 = (M₂)(0.500 L)

M₂ = 6.48 M

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If the two atoms participating in a bond have an electron negativity difference of 1.9 , what type of of bond would they be part
brilliants [131]

Answer:

Polar covalent bond.

Explanation:

When the bond is formed between the atoms by sharing the electrons the bond thus have covalent character.   The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive.  When the electronegativity difference is less than 0.4 the bond is non polar covalent.

When bonded atoms have greater electronegativity difference i.e 2 or greater than two the bond is ionic because electron is transfer from low electronegative atom to highest electronegative atom.

For example:

In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive.

In case of H₂, Cl₂, Br₂ the bond has very high covalent character because of zero electronegativity difference.

7 0
3 years ago
Calcium cyclamate, Ca(C₆H₁₁NHSO₃)₂, is an artificial sweetener used in many countries around the world but is banned in the Unit
xeze [42]

Answer:

2HC₆H₁₁NHSO₃ + BaCO₃ → Ba(C₆H₁₁NHSO₃)₂ + H₂CO₃;

Ba(C₆H₁₁NHSO₃)₂ + H₂SO₄ → BaSO₄ + 2HC₆H₁₁NHSO₃;

2HC₆H₁₁NHSO₃ + Ca(OH)₂ → Ca(C₆H₁₁NHSO₃)₂ + 2H₂O

Explanation:

First, let's see the reactants for the first reaction and how they dissociate:

HC₆H₁₁NHSO₃ → H⁺ + C₆H₁₁NHSO₃⁻

BaCO₃ → Ba²⁺ + CO₃²⁻ (Barium is from group 2, so its cation has charge +2)

So, to form the products, the cation of one will join the anion of others. The amount of the cation will be the charge of the anion, and the amount of the anion will be the charge of the cation:

H⁺ + CO₃²⁻ → H₂CO₃

Ba²⁺ + C₆H₁₁NHSO₃⁻ → Ba(C₆H₁₁NHSO₃)₂

The reaction then is:

HC₆H₁₁NHSO₃ + BaCO₃ → Ba(C₆H₁₁NHSO₃)₂ + H₂CO₃

The number of elements must be the same on both sides, so the balanced equation is

2HC₆H₁₁NHSO₃ + BaCO₃ → Ba(C₆H₁₁NHSO₃)₂ + H₂CO₃

The treatment with H₂SO₄ will produce:

H₂SO₄ → 2H⁺ + SO₄⁻²

Ba(C₆H₁₁NHSO₃)₂ → Ba²⁺ + C₆H₁₁NHSO₃⁻

The balanced reaction will be then:

Ba(C₆H₁₁NHSO₃)₂ + H₂SO₄ → BaSO₄ + 2HC₆H₁₁NHSO₃

In the last step, HC₆H₁₁NHSO₃ will react with Ca(OH)₂

HC₆H₁₁NHSO₃ → H⁺ + C₆H₁₁NHSO₃⁻

Ca(OH)₂ → Ca²⁺ + 2OH⁻

The balance reaction will be:

2HC₆H₁₁NHSO₃ + Ca(OH)₂ → Ca(C₆H₁₁NHSO₃)₂ + 2H₂O

3 0
3 years ago
If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w
Nata [24]

4.1g

Explanation:

Given parameters:

Mass of carbon dioxide = 15g

Mass of oxygen gas = 11g

Unknown:

Mass of carbon consumed = ?

Solution:

   Equation of the reaction:

                                              C +  O₂   →   CO₂

    To solve this problem from the balanced equation,  we have to use the amount of product formed and work to Carbon. This is because, we are sure of the amount of carbon dioxide formed but the amount of the given oxygen gas used is not precise.

  Number of moles of CO₂ = \frac{mass}{molar mass}

Molar mass of CO₂ = 12 + (16 x2) = 44g/mol

   Number of moles of CO₂ = \frac{15}{44} = 0.34mole

From the equation of the reaction;

              1 mole of CO₂  is produced from 1 mole of C

           0.34mole of CO₂  will produce 0.34mole of C

Mass of carbon reacting = number of moles x molar mass = 0.34 x 12 = 4.1g

Learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

4 0
3 years ago
A scientist is raising the temperature of a
Arlecino [84]

Answer:

nothing

Explanation:

Here no result have been found yet..

Therfore we cannot determine which variable is dependent and which is not

8 0
1 year ago
Suppose much of an old forest will be used for farmland. A certain portion of the land will be set aside as wildlife habitat. Yo
WITCHER [35]

Answer:

A certain portion of the land will be set aside as wildlife habitat

7 0
2 years ago
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