Question

If a solution of HCI has a molarity of 2.70M and a volume of 1.20L, what was the initial molarity if the initial volume was 0.500L?
O 6.4M
O 3.24M
O 1.13M
O 6.48M
+

Answer 1

Answer:

6.48 M

Explanation:

M₁V₁ = M₂V₂

Step 1: Define

Molarity₁ = 2.70 M

Volume₁ = 1.20 L

Molarity₂ = unknown

Volume₂ = 0.500 L

Step 2: Substitute and Evaluate for M₂

(2.70 M)(1.20 L) = (M₂)(0.500 L)

3.24 = (M₂)(0.500 L)

M₂ = 6.48 M