If solution A has a pH that is four pH units greater than that of solution B, how much greater is the H3O+ concentration in solu
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<span>molecular weight of C4H10 is = 58.1 grams
moles of butane = </span>
= 0.0258
Multiply the number of moles by Avogadro's number. This will let you obtain the number of butane molecules:
<span>0.0258 x 6.023 x 10^{23} molecules of butane = 1.5538 * 10^22 molecules
of butane
</span>
<span>Now multiply this number by four (due to four carbon atoms per butane molecule) to obtain the answer:
</span>
so, no. of carbon atoms = 4 x 1.5538 x 10^22 = 6.21 x 10^22 atoms
moles of butane = </span>
Multiply the number of moles by Avogadro's number. This will let you obtain the number of butane molecules:
<span>0.0258 x 6.023 x 10^{23} molecules of butane = 1.5538 * 10^22 molecules
of butane
</span>
<span>Now multiply this number by four (due to four carbon atoms per butane molecule) to obtain the answer:
</span>
so, no. of carbon atoms = 4 x 1.5538 x 10^22 = 6.21 x 10^22 atoms