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Alex17521 [72]
2 years ago
8

Determine which is the control group and which is the experimental group in the following scenario ( Scientists are testing a ne

w kind of aspirin to see whether it will relieve headaches. They give one group of volunteers the aspirin. They give another group of volunteers pills that look like aspirin but are actually sugar pills)
Answer this and you will get brainiest WITH NO VIRUS LINKS OR REPORT YOU
Chemistry
2 answers:
quester [9]2 years ago
7 0
The group that were given sugar pills
Daniel [21]2 years ago
3 0

Answer:

The group given the sugar pills.

Explanation:

The control group is the ones given sugar pills because they did not get the experimental aspirin

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Elodia [21]

Denaturation is the action of disrupting the three-dimensional shape of a protein.

4 0
3 years ago
In J.J. Thomson's plum pudding model of the atom, the plums represent
Maksim231197 [3]
The answer is A. The “plums” or the “raisins” of the pudding are the electrons. The actual “pudding” is the nucleus, which is made up of protons and neutrons, so it is a large positively charged mass.
Hope this helps!!! ^v^
8 0
3 years ago
4/5(2x 5)−4=1
uysha [10]
 5/8=0.625 4/5=.8


5/8 because 5/8=0.625 and because its 2x you multiply 0.625 by 2=1.25 then you do 1.25+5=6.25 4/5=.8    6.25 times .8=5 5-4=1   


X=5/8 or 0.625

5 0
3 years ago
From the following balanced equation,
ArbitrLikvidat [17]

Answer:

9.72 grams.

Explanation:

From the equation, 4 moles of NH₃ produce 6 moles of  water.

Therefore the reaction to product ratio of  NH₃ to H₂O is 4:6

and 2:3 into its simplest form.

The number of moles of NH₃ in 6.12 g is:

Number of moles=mass/ RMM

=6.12 g/17 G/mol

=0.36 moles.

Therefore the number of moles of H₂O produced is calculated as follows.

(0.36 Moles×3)2 = 0.54 moles

Mass= Number of moles × RMM

=0.54 moles×18g/mol

=9.72 grams.

6 0
3 years ago
If 3.53 g of CuNO, is dissolved in water to make a 0.330 M solution, what is the volume of the solution in milliliters?
solmaris [256]

Answer:

84.8 mL

Explanation:

From the question given above, the following data were obtained:

Mass of CuNO₃ = 3.53 g

Molarity of CuNO₃ = 0.330 M

Volume of solution =?

Next, we shall determine the number of mole in 3.53 g of CuNO₃. This can be obtained as follow:

Mass of CuNO₃ = 3.53 g

Molar mass of CuNO₃ = 63.5 + 14 + (16×3)

= 63.5 + 14 + 48

= 125.5 g/mol

Mole of CuNO₃ =?

Mole = mass / Molar mass

Mole of CuNO₃ = 3.53 / 125.5

Mole of CuNO₃ = 0.028 moles

Next, we shall determine the volume of the solution. This can be obtained as follow:

Molarity of CuNO₃ = 0.330 M

Mole of CuNO₃ = 0.028 moles

Volume of solution =?

Molarity = mole /Volume

0.330 = 0.028 / Volume

Cross multiply

0.330 × Volume = 0.028

Divide both side by 0.330

Volume = 0.028 / 0.330

Volume = 0.0848 L

Finally, we shall convert 0.0848 L to millilitres (mL). This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.0848 L = 0.0848 L × 1000 mL / 1 L

0.0848 L = 84.8 mL

Therefore, the volume of the solution is 84.8 mL.

8 0
2 years ago
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