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dangina [55]
3 years ago
11

How many times larger is 3 x 10^8 than 3 x 10^2

Mathematics
2 answers:
masya89 [10]3 years ago
7 0

Step-by-step explanation:

so basically you multiple the equations aka solve them individually ,Then she which number is greater and subtract it

Oksana_A [137]3 years ago
4 0

Answer:

{10}^{6}

Step-by-step explanation:

\frac{3 \times  {10}^{8} }{3 \times  {10}^{2} }  =  \frac{ {10}^{8} }{ {10}^{2} }  =  {10}^{6}  \\  \\  \therefore \: 3 \times  {10}^{8} \: is \: {10}^{6}  \: times \: larger \: than \: 3 \times  {10}^{2}

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12x-39≤9 AND −4x+3<−6
Elza [17]

Answer:

9/4<x≤4 or all real numbers

Step-by-step explanation:

I'm not sure what you are asking

4 0
3 years ago
A rectangular prism has the dimensions 8 feet by 3 feet by 5 feet. What is the surface area of the prism?
raketka [301]

Answer:

A=158

Step-by-step explanation: SA = 2 × l × w  +  2 × l × h  +  2 × w × h

8 0
3 years ago
Fine The slope of the line on the graph
Brrunno [24]

Take any 2 points through which the line on graph passes,

(0,-1) =(x₁,y₁)

& (2,-4)=(x₂,y₂)

slope=(y₂-y₁)/(x₂-x₁)

=[-4-(-1)]/(2-0)

=-3/2

3 0
3 years ago
Given the following right triangle, find cose, sine, tane sececsce, and cote. Do not
IgorLugansk [536]

Step-by-step explanation:

Use the Pythagorean theorem:

leg^2+leg^2=hypotenuse^2

We have

leg=4,\ hypotenuse=10

Substitute:

4^2+leg^2=10^2

16+leg^2=100             <em>subtract 16 from both sides</em>

leg^2=84\to leg=\sqrt{84}\\\\leg=\sqrt{(4)(21)}\\\\leg=\sqrt4\cdot\sqrt{21}\\\\leg=2\sqrt{21}

sine=\dfrac{opposite}{hypotenuse}\\\\cosine=\dfrac{adjacent}{hypotenuse}\\\\tangent=\dfrac{opposite}{adjacent}\\\\cotangent=\dfrac{adjacent}{opposite}\\\\secant=\dfrac{hypotenuse}{adjacent}\\\\cosecant=\dfrac{hypotenuse}{opposite}

Substitute:

hypotenuse=10,\ opposite=4,\ adjacent=2\sqrt{21}

\sin\theta=\dfrac{4}{10}=\dfrac{2}{5}\\\\\cos\theta=\dfrac{2\sqrt{21}}{10}=\dfrac{\sqrt{21}}{5}\\\\\tan\theta=\dfrac{4}{2\sqrt{21}}=\dfrac{2}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{2\sqrt{21}}{21}\\\\\cot\theta=\dfrac{2\sqrt{21}}{4}=\dfrac{\sqrt{21}}{2}\\\\\sec\theta=\dfrac{10}{2\sqrt{21}}=\dfrac{5}{\sqrt{21}}\cdot\dfrac{\sqrt{21}}{\sqrt{21}}=\dfrac{5\sqrt{21}}{21}\\\\\csc\theta=\dfrac{10}{4}=\dfrac{5}{2}

5 0
3 years ago
Which team has the best winning percentage?
Sonja [21]
10 wins/ 6 losses= 1.667

13 wins/ 7 losses= 1.857..

32 wins/ 18 losses= 1.77..

6 wins/ 3 losses= 2

The last team has the highest win to loss ratio, and therefore has the highest winning percentage.

Final answer: Last team, 6 wins and 3 losses
4 0
3 years ago
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