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3 years ago

118 meters in 2 seconds, how many meters in 11 seconds?

Mathematics

2 answers:

erastova [34]3 years ago

3 0

Answer:

It would be 649

Step-by-step explanation:

118 ÷ 2= 59

59 x 11= 649

Andre45 [30]3 years ago

3 0

Answer:

649m

Step-by-step explanation:

$\frac{118m}{2s} =\frac{59m}{s}$

so that 59m/s we multiply by 11s

$\frac{59m}{s} (11s)=649m$

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Find the area of the figure. round your answer to the nearest hundredth

liraira [26]

Answer: 84.14

Step-by-step explanation:

Area of the rectangle is L*W=B*H

14*5=70

To find the area of the half circle we must use the formula pi r^2/2

r=radius

and the radius is 6 because we add 4 and 4 and need to get to 14

because the line below it is 14 and it is a rectangle so the lengths are the same.

Diameter=6

So radius =3

pi (3)^2/2=

9/2 pi + 70=

84.14

6 0

2 years ago

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Add 1/4 and 5/8 by using the giant one to create a common denominator <br> thanks

Sedbober [7]

Answer:

7/8

Step-by-step explanation:

1/4×2=2/8....2/8+5/8=7/8

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2 years ago

Barry is trying to calculate the distance between point E(3, 1) and point F(4, 7). Which of the following expressions will he us

maxonik [38]

D=√((7-1)^2+(4-3)^2)=√37

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2 years ago

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A cylindrical tank is filled with 66.85 mm3 of fuel. The area of the base of the cylinder is 15 mm2. What is the height of the f

Rashid [163]

Volume = (Area of the base)x(Height)
66.85 = 15(H)
66.85/15 = H
H = 4.4567

The height is 4.4567mm.

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3 years ago

Help me asap! I will give you marks

Law Incorporation [45]

Recall the binomial theorem.

$(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k$

1. The binomial expansion of $\left(1+\frac x3\right)^7$ is

$\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}$

Observe that

$k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x$

$k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2$

When we multiply these by $8-9x$ ,

• $8$ and $\frac73 x^2$ combine to make $\frac{56}3 x^2$

• $-9x$ and $\frac73 x$ combine to make $-\frac{63}3 x^2 = -21x^2$

and the sum of these terms is

$\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}$

2. The binomial expansion is

$\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k$

We get the $a^6b^2$ term when $k=2$ :

$k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2$

6 0

1 year ago