So basically, what you want to do, is just add or subtract everything together.

Think of -9 as a number 9 to the left of a number line, and then you're adding 11 units, moving -9 11 times to the right. Once you do this, you get 2. Now, adding negative 9 is the same thing as moving 2 9 times to the right. Once you do that as well, you'll get -7. And then just move -7 12 units to the right on the number line and you'll get 5.

Haha that was a really bad explanation, but hope I helped!

7 0

3 years ago

A man has saved $640 during the first month,$720 in the second month and $800 in the third month. If he continues his savings in

bija089 [108]

Answer:

Step-by-step explanation:

An arithmetic progression is a list of numbers a1, a2, a3 ………….. an in which each term is obtained by adding a fixed number to the preceding term except the first term.

This fixed number is called the common difference( d ) of the AP. Common difference of an AP will be the difference between any two consecutive terms.

a2= a1+d

a3= a2+d

a4= a3+d

……..

an= an-1+d ………

Each of the numbers in the list is called a term .

Method to find the common difference :

d = a2 - a1 or a3 - a2 or a4 - a3...

General form of an AP.:

a, a+d, a+2d, a+3d…….

Here a is the first term and d is common difference.

General term or nth term of A.P

The general term or nth term of A.P is given by an or tn = a + (n – 1)d, where a = a1 is the first term, d is the common difference and n is the number of term.

SOLUTION :

Given -

A man saved in the first month,in the second month ,in the third month… are 640, 720, 800 .. which forms a sequence(AP).

Here, a1 or t1 = 640 , a2 or t2= 720, a3 or t3 = 800

d = t2 – t1

d= 720- 640

d= 80

tn = a + (n-1) d

t25 = 640 + (25 - 1) 80

t25 = 640 + 24 (80)

t25= 640 + 1920

t25 = 2560

Hence, his Saving will be 2560 in the 25th month.

Hope this helps,from Armax.

8 0

2 years ago