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Nitella [24]
2 years ago
6

If a cylinder has a volume of 120 cm3 and a cone has a volume of 360 cm3, is it possible that the two cones have congruent bases

and congruent heights?
Mathematics
1 answer:
Mariulka [41]2 years ago
4 0

No, the cone and the cylinder can't have congruent heights and bases.

<h3>is it possible that the two cones have congruent bases and congruent heights?</h3>

The volume of a cylinder of radius R and height H is:

V = pi*R^2*H

And for a cone of radius R and height H is:

V = pi*R^2*H/3

So, for the same dimensions R and H, the cone has 1/3 of the volume of the cylinder.

Here, the cylinder has a volume of 120cm³ and the cone a volume of 360cm³, so the cone has 3 times the volume of the cylinder.

This means that the measures must be different, so the cone and the cylinder can't have congruent heights and bases.

If you want to learn more about volumes:

brainly.com/question/1972490

#SPJ1

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3 years ago
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\text{Let the side of square 1, square 2 and square 3 be x, y and z respectively.}\\\\\text{Given that,}\\\\\text{Perimeter of square 1,~~ p  =100 units.}\\\\\text{So}~ x=\dfrac p 4 =  \dfrac{100}4 =25~\text{units.}\\\\\\\text{Area of square 2, a = 225 units}^2\\\\\text{So}~y = \sqrt{a} = \sqrt {225} = 15~ \text{units.}\\\\\text{Use Pythagorean theorem to find z}^2\\\\x^2 =y^2 +z^2 \\\\\implies 25^2 = 15^2 +z^2\\\\\implies z^2 = 625 - 225 = 400\\\\\\

\text{Hence the area of square 3 is 400 units}^2.

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I hope this is good enough:

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