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Nitella [24]
2 years ago
6

If a cylinder has a volume of 120 cm3 and a cone has a volume of 360 cm3, is it possible that the two cones have congruent bases

and congruent heights?
Mathematics
1 answer:
Mariulka [41]2 years ago
4 0

No, the cone and the cylinder can't have congruent heights and bases.

<h3>is it possible that the two cones have congruent bases and congruent heights?</h3>

The volume of a cylinder of radius R and height H is:

V = pi*R^2*H

And for a cone of radius R and height H is:

V = pi*R^2*H/3

So, for the same dimensions R and H, the cone has 1/3 of the volume of the cylinder.

Here, the cylinder has a volume of 120cm³ and the cone a volume of 360cm³, so the cone has 3 times the volume of the cylinder.

This means that the measures must be different, so the cone and the cylinder can't have congruent heights and bases.

If you want to learn more about volumes:

brainly.com/question/1972490

#SPJ1

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Answer:

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Step-by-step explanation:

Given the expression

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\frac{\left(\sqrt{200}\:+\:\sqrt{128}\:\right)}{2}=\frac{10\sqrt{2}+8\sqrt{2}}{2}

Add similar elements:  10\sqrt{2}+8\sqrt{2}=18\sqrt{2}

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Divide the numbers: 18/2 = 9

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\frac{\left(\sqrt{200}\:+\:\sqrt{128}\:\right)}{2}=9\sqrt{2}

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Refer to the diagram below.

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Let Q = ∠RQS.
Let S = ∠RSQ

According to the Law of Sines,
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Because the sum of angles in a triangle is 180°, therefore
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